algorithm-in-python/math/numberTheory/isPrime.py

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2018-10-02 21:24:06 +08:00
''' mbinary
#########################################################################
# File : isPrime.py
# Author: mbinary
# Mail: zhuheqin1@gmail.com
2019-01-31 12:09:46 +08:00
# Blog: https://mbinary.xyz
2018-10-02 21:24:06 +08:00
# Github: https://github.com/mbinary
# Created Time: 2018-03-04 21:34
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# Description:
#########################################################################
'''
from random import randint
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def quickMulMod(a,b,m):
'''a*b%m, quick'''
ret = 0
while b:
if b&1:
ret = (a+ret)%m
b//=2
a = (a+a)%m
return ret
def quickPowMod(a,b,m):
'''a^b %m, quick, O(logn)'''
ret =1
while b:
if b&1:
ret =quickMulMod(ret,a,m)
b//=2
a = quickMulMod(a,a,m)
return ret
def isPrime(n,t=5):
'''miller rabin primality test, a probability result
t is the number of iteration(witness)
'''
t = min(n-3,t)
if n<2:
print('[Error]: {} can\'t be classed with prime or composite'.format(n))
return
if n==2: return True
d = n-1
r = 0
while d%2==0:
r+=1
d//=2
tested=set()
for i in range(t):
a = randint(2,n-2)
while a in tested:
a = randint(2,n-2)
tested.add(a)
x= quickPowMod(a,d,n)
if x==1 or x==n-1: continue #success,
for j in range(r-1):
x= quickMulMod(x,x,n)
if x==n-1:break
else:
return False
return True
'''
we shouldn't use Fermat's little theory
Namyly:
For a prime p, and any number a where (a,n)=1
a ^(p-1) \equiv 1 (mod p)
The inverse theorem of it is not True.
a counter-example: 2^340 \equiv 1 (mod 341), but 341 is a composite
'''
class primeSieve:
'''sieve of Eratosthenes, It will be more efficient when judging many times'''
primes = [2,3,5,7,11,13]
def isPrime(self,x):
if x<=primes[-1]:
return twoDivideFind(x,self.primes)
while x>self.primes[-1]:
left = self.primes[-1]
right = (left+1)**2
lst = []
for i in range(left,right):
for j in self.primes:
if i%j==0:break
else:lst.append(i)
self.primes+=lst
return twoDivideFind(x,lst)
def nPrime(n):
'''return the n-th prime'''
i=n-len(self.primes)
last = self.primes[-1]
for _ in range(i):
while 1:
last +=2
for p in self.primes:
if last%p==0:
break
else:
self.primes.append(last)
break
return self.primes[n-1]
def twoDivideFind(x,li):
a,b = 0, len(li)
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while a<=b:
mid = (a+b)//2
if li[mid]<x:a=mid+1
elif li[mid]>x: b= mid-1
else:return mid
return -1
if __name__=='__main__':
n = 100
print('prime numbers below',n)
print([i for i in range(n) if isPrime(i)])
while 1:
n = int(input('n: '))
print(isPrime(n))