Separate challenge for better compression

This commit is contained in:
Ashhar Hasan 2015-12-19 02:15:14 +05:30
parent 206841bc5d
commit 7d6b374380
4 changed files with 449 additions and 0 deletions

View File

@ -0,0 +1,165 @@
{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<small><i>This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges).</i></small>"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Challenge Notebook"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Problem: Compress a string such that 'AAABCCDDDD' becomes 'A3BCCD4'. Only compress the string if it saves space.\n",
"\n",
"* [Constraints](#Constraints)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
"* [Code](#Code)\n",
"* [Unit Test](#Unit-Test)\n",
"* [Solution Notebook](#Solution-Notebook)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Constraints\n",
"\n",
"* Can we assume the string is ASCII?\n",
" * Yes\n",
" * Note: Unicode strings could require special handling depending on your language\n",
"* Can you use additional data structures? \n",
" * Yes\n",
"* Is this case sensitive?\n",
" * Yes"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
"* None -> None\n",
"* '' -> ''\n",
"* 'AABBCC' -> 'AABBCC'\n",
"* 'AAABCCDDDD' -> 'A3BCCD4'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm\n",
"\n",
"Refer to the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/arrays_strings/compress/compress_solution.ipynb). If you are stuck and need a hint, the solution notebook's algorithm discussion might be a good place to start."
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": false
},
"outputs": [],
"source": [
"def compress_string(string):\n",
" # TODO: Implement me\n",
" pass"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Unit Test"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"\n",
"\n",
"**The following unit test is expected to fail until you solve the challenge.**"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": false
},
"outputs": [],
"source": [
"# %load test_compress.py\n",
"from nose.tools import assert_equal\n",
"\n",
"\n",
"class TestCompress(object):\n",
"\n",
" def test_compress(self, func):\n",
" assert_equal(func(None), None)\n",
" assert_equal(func(''), '')\n",
" assert_equal(func('AABBCC'), 'AABBCC')\n",
" assert_equal(func('AAABCCDDDD'), 'A3BCCD4')\n",
" print('Success: test_compress')\n",
"\n",
"\n",
"def main():\n",
" test = TestCompress()\n",
" test.test_compress(compress_string)\n",
"\n",
"\n",
"if __name__ == '__main__':\n",
" main()"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Solution Notebook\n",
"\n",
"Review the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/arrays_strings/compress/compress_solution.ipynb) for a discussion on algorithms and code solutions."
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 3",
"language": "python",
"name": "python3"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 3
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.4.3"
}
},
"nbformat": 4,
"nbformat_minor": 0
}

View File

@ -0,0 +1,263 @@
{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<small><i>This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges).</i></small>"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Solution Notebook"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Problem: Compress a string such that 'AAABCCDDDD' becomes 'A3BCCD4'. Only compress the string if it saves space.\n",
"\n",
"* [Constraints](#Constraints)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
"* [Code](#Code)\n",
"* [Unit Test](#Unit-Test)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Constraints\n",
"\n",
"* Can we assume the string is ASCII?\n",
" * Yes\n",
" * Note: Unicode strings could require special handling depending on your language\n",
"* Can you use additional data structures? \n",
" * Yes\n",
"* Is this case sensitive?\n",
" * Yes"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
"* None -> None\n",
"* '' -> ''\n",
"* 'AABBCC' -> 'AABBCC'\n",
"* 'AAABCCDDDD' -> 'A3BCCD4'"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm\n",
"\n",
"Since Python strings are immutable, we'll use a list of characters to build the compressed string representation. We'll then convert the list to a string.\n",
"\n",
"* Calculate the size of the compressed string\n",
" * Note the constraint about compressing only if it saves space\n",
"* If the compressed string size is >= string size, return string\n",
"* Create compressed_string\n",
" * For each char in string\n",
" * If char is the same as last_char, increment count\n",
" * Else\n",
" * If the count is more than 2\n",
" * Append last_char to compressed_string\n",
" * append count to compressed_string\n",
" * count = 1\n",
" * last_char = char\n",
" * If count is 1\n",
" * Append last_char to compressed_string\n",
" * count = 1\n",
" * last_char = char\n",
" * If count is 2\n",
" * Append last_char to compressed_string\n",
" * Append last_char to compressed_string once more\n",
" * count = 1\n",
" * last_char = char\n",
" * Append last_char to compressed_string\n",
" * Append count to compressed_string\n",
" * Return compressed_string\n",
"\n",
"Complexity:\n",
"* Time: O(n)\n",
"* Space: O(n)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
},
"outputs": [],
"source": [
"def compress_string(string):\n",
"\tif string is None or len(string) == 0:\n",
"\t\treturn string\n",
"\n",
"\t# Calculate the size of the compressed string\n",
"\tsize = 0\n",
"\tlast_char = string[0]\n",
"\tfor char in string:\n",
"\t\tif char != last_char:\n",
"\t\t\tsize += 2\n",
"\t\t\tlast_char = char\n",
"\tsize += 2\n",
"\n",
"\t# If the compressed string size is greater than\n",
"\t# or equal to string size, return original string\n",
"\tif size >= len(string):\n",
"\t\treturn string\n",
"\n",
"\t# Create compressed_string\n",
"\t# New objective:\n",
"\t\t# Single characters are to be left as is\n",
"\t\t# Double characters are to be left as are\n",
"\tcompressed_string = list()\n",
"\tcount = 0\n",
"\tlast_char = string[0]\n",
"\tfor char in string:\n",
"\t\tif char == last_char:\n",
"\t\t\tcount += 1\n",
"\t\telse:\n",
"\t\t\t# Do the old compression tricks only if count exceeds two\n",
"\t\t\tif count > 2:\n",
"\t\t\t\tcompressed_string.append(last_char)\n",
"\t\t\t\tcompressed_string.append(str(count))\n",
"\t\t\t\tcount = 1\n",
"\t\t\t\tlast_char = char\n",
"\t\t\t# If count is either 1 or 2 (or 0?)\n",
"\t\t\t# FIXME: CAN COUNT BE 0?\n",
"\t\t\telse:\n",
"\t\t\t\t# If count is 1, leave the char as is\n",
"\t\t\t\tif count == 1:\n",
"\t\t\t\t\tcompressed_string.append(last_char)\n",
"\t\t\t\t\tcount = 1\n",
"\t\t\t\t\tlast_char = char\n",
"\t\t\t\t# If count is 2, append the character twice\n",
"\t\t\t\telse:\n",
"\t\t\t\t\tcompressed_string.append(last_char)\n",
"\t\t\t\t\tcompressed_string.append(last_char)\n",
"\t\t\t\t\tcount = 1\n",
"\t\t\t\t\tlast_char = char\n",
"\tcompressed_string.append(last_char)\n",
"\tcompressed_string.append(str(count))\n",
"\n",
"\t# Convert the characters in the list to a string\n",
"\treturn \"\".join(compressed_string)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Unit Test"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Overwriting test_compress.py\n"
]
}
],
"source": [
"%%writefile test_compress.py\n",
"from nose.tools import assert_equal\n",
"\n",
"\n",
"class TestCompress(object):\n",
"\n",
" def test_compress(self, func):\n",
" assert_equal(func(None), None)\n",
" assert_equal(func(''), '')\n",
" assert_equal(func('AABBCC'), 'AABBCC')\n",
" assert_equal(func('AAABCCDDDD'), 'A3BCCD4')\n",
" assert_equal(func('aaBCCEFFFFKKMMMMMMP taaammanlaarrrr seeeeeeeeek tooo'), 'aaBCCEF4KKM6P ta3mmanlaar4 se9k to3')\n",
" print('Success: test_compress')\n",
"\n",
"\n",
"def main():\n",
" test = TestCompress()\n",
" test.test_compress(compress_string)\n",
"\n",
"\n",
"if __name__ == '__main__':\n",
" main()"
]
},
{
"cell_type": "code",
"execution_count": 7,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Success: test_compress\n"
]
}
],
"source": [
"%run -i test_compress.py"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": []
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 3",
"language": "python",
"name": "python3"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 3
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.4.3"
}
},
"nbformat": 4,
"nbformat_minor": 0
}

View File

@ -0,0 +1,21 @@
from nose.tools import assert_equal
class TestCompress(object):
def test_compress(self, func):
assert_equal(func(None), None)
assert_equal(func(''), '')
assert_equal(func('AABBCC'), 'AABBCC')
assert_equal(func('AAABCCDDDD'), 'A3BCCD4')
assert_equal(func('aaBCCEFFFFKKMMMMMMP taaammanlaarrrr seeeeeeeeek tooo'), 'aaBCCEF4KKM6P ta3mmanlaar4 se9k to3')
print('Success: test_compress')
def main():
test = TestCompress()
test.test_compress(compress_string)
if __name__ == '__main__':
main()