algorithm-in-python/dataStructure/trie/maxXor.py
2019-01-31 12:09:46 +08:00

71 lines
1.9 KiB
Python

#coding: utf-8
''' mbinary
#######################################################################
# File : maxXor.py
# Author: mbinary
# Mail: zhuheqin1@gmail.com
# Blog: https://mbinary.xyz
# Github: https://github.com/mbinary
# Created Time: 2018-12-22 09:51
# Description:
maximum_xor_of_two_numbers_in_an_array:
using trie data structure
O(k*n) where n=length(array),k is the max length of radix of num
#######################################################################
'''
class node:
def __init__(self,key,hasKey = False):
self.key = key
self.hasKey = hasKey
self.children={}
def __getitem__(self,key):
return self.children[key]
def __len__(self):
return len(self.children)
def __setitem__(self,key,val):
self.children[key]=val
def __contains__(self,key):
return key in self.children
class trie:
def __init__(self,maxDepth=32):
self.root=node(None)
self.maxDepth = maxDepth
def add(self,num):
nd = self.root
s = bin(num)[2:].rjust(self.maxDepth,'0')
for n in s:
if n not in nd:
nd[n]=node(n)
nd=nd[n]
def search(self,num):
ret = 0
nd = self.root
s = bin(num)[2:].rjust(self.maxDepth,'0')
for n in s:
# note that it's the flip bit
flip = '1' if n=='0' else '0'
if flip in nd:
ret=ret*2+1
nd=nd[flip]
else:
ret*=2
nd=nd[n]
return ret
def findMaximumXOR(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
if not nums:return 0
n = len(bin(max(nums)))-1
t = trie(n)
for i in nums:t.add(i)
return max(t.search(i) for i in nums)
if __name__=='__main__':
from random import randint
nums = [randint(1,int(1e18)) for i in 100]
findMaximumXOR(nums)