27 lines
958 B
Java
27 lines
958 B
Java
# 66. 构建乘积数组
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## 题目链接
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[NowCoder](https://www.nowcoder.com/practice/94a4d381a68b47b7a8bed86f2975db46?tpId=13&tqId=11204&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
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## 题目描述
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给定一个数组 A[0, 1,..., n-1]，请构建一个数组 B[0, 1,..., n-1]，其中 B 中的元素 B[i]=A[0]\*A[1]\*...\*A[i-1]\*A[i+1]\*...\*A[n-1]。要求不能使用除法。
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/4240a69f-4d51-4d16-b797-2dfe110f30bd.png" width="250px"> </div><br>
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## 解题思路
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```java
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public int[] multiply(int[] A) {
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int n = A.length;
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int[] B = new int[n];
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for (int i = 0, product = 1; i < n; product *= A[i], i++) /* 从左往右累乘 */
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B[i] = product;
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for (int i = n - 1, product = 1; i >= 0; product *= A[i], i--) /* 从右往左累乘 */
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B[i] *= product;
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return B;
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}
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```
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