51 lines
1.2 KiB
Java
51 lines
1.2 KiB
Java
# 57.2 和为 S 的连续正数序列
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[NowCoder](https://www.nowcoder.com/practice/c451a3fd84b64cb19485dad758a55ebe?tpId=13&tqId=11194&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
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## 题目描述
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输出所有和为 S 的连续正数序列。
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例如和为 100 的连续序列有：
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```
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[9, 10, 11, 12, 13, 14, 15, 16]
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[18, 19, 20, 21, 22]。
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```
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## 解题思路
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```java
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public ArrayList<ArrayList<Integer>> FindContinuousSequence(int sum) {
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ArrayList<ArrayList<Integer>> ret = new ArrayList<>();
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int start = 1, end = 2;
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int curSum = 3;
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while (end < sum) {
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if (curSum > sum) {
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curSum -= start;
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start++;
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} else if (curSum < sum) {
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end++;
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curSum += end;
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} else {
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ArrayList<Integer> list = new ArrayList<>();
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for (int i = start; i <= end; i++)
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list.add(i);
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ret.add(list);
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curSum -= start;
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start++;
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end++;
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curSum += end;
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}
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}
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return ret;
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}
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```
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