CS-Notes/notes/26. 树的子结构.md

26. 树的子结构

NowCoder

题目描述

解题思路

public boolean HasSubtree(TreeNode root1, TreeNode root2) {
    if (root1 == null || root2 == null)
        return false;
    return isSubtreeWithRoot(root1, root2) || HasSubtree(root1.left, root2) || HasSubtree(root1.right, root2);
}

private boolean isSubtreeWithRoot(TreeNode root1, TreeNode root2) {
    if (root2 == null)
        return true;
    if (root1 == null)
        return false;
    if (root1.val != root2.val)
        return false;
    return isSubtreeWithRoot(root1.left, root2.left) && isSubtreeWithRoot(root1.right, root2.right);
}