325 lines
5.8 KiB
Markdown
325 lines
5.8 KiB
Markdown
<!-- GFM-TOC -->
|
||
* [栈](#栈)
|
||
* [1. 数组实现](#1-数组实现)
|
||
* [2. 链表实现](#2-链表实现)
|
||
* [队列](#队列)
|
||
<!-- GFM-TOC -->
|
||
|
||
|
||
# 栈
|
||
|
||
```java
|
||
public interface MyStack<Item> extends Iterable<Item> {
|
||
|
||
MyStack<Item> push(Item item);
|
||
|
||
Item pop() throws Exception;
|
||
|
||
boolean isEmpty();
|
||
|
||
int size();
|
||
|
||
}
|
||
```
|
||
|
||
## 1. 数组实现
|
||
|
||
```java
|
||
public class ArrayStack<Item> implements MyStack<Item> {
|
||
|
||
// 栈元素数组,只能通过转型来创建泛型数组
|
||
private Item[] a = (Item[]) new Object[1];
|
||
|
||
// 元素数量
|
||
private int N = 0;
|
||
|
||
|
||
@Override
|
||
public MyStack<Item> push(Item item) {
|
||
check();
|
||
a[N++] = item;
|
||
return this;
|
||
}
|
||
|
||
|
||
@Override
|
||
public Item pop() throws Exception {
|
||
|
||
if (isEmpty()) {
|
||
throw new Exception("stack is empty");
|
||
}
|
||
|
||
Item item = a[--N];
|
||
|
||
check();
|
||
|
||
// 避免对象游离
|
||
a[N] = null;
|
||
|
||
return item;
|
||
}
|
||
|
||
|
||
private void check() {
|
||
|
||
if (N >= a.length) {
|
||
resize(2 * a.length);
|
||
|
||
} else if (N > 0 && N <= a.length / 4) {
|
||
resize(a.length / 2);
|
||
}
|
||
}
|
||
|
||
|
||
/**
|
||
* 调整数组大小,使得栈具有伸缩性
|
||
*/
|
||
private void resize(int size) {
|
||
|
||
Item[] tmp = (Item[]) new Object[size];
|
||
|
||
for (int i = 0; i < N; i++) {
|
||
tmp[i] = a[i];
|
||
}
|
||
|
||
a = tmp;
|
||
}
|
||
|
||
|
||
@Override
|
||
public boolean isEmpty() {
|
||
return N == 0;
|
||
}
|
||
|
||
|
||
@Override
|
||
public int size() {
|
||
return N;
|
||
}
|
||
|
||
|
||
@Override
|
||
public Iterator<Item> iterator() {
|
||
|
||
// 返回逆序遍历的迭代器
|
||
return new Iterator<Item>() {
|
||
|
||
private int i = N;
|
||
|
||
@Override
|
||
public boolean hasNext() {
|
||
return i > 0;
|
||
}
|
||
|
||
@Override
|
||
public Item next() {
|
||
return a[--i];
|
||
}
|
||
};
|
||
|
||
}
|
||
}
|
||
```
|
||
|
||
## 2. 链表实现
|
||
|
||
需要使用链表的头插法来实现,因为头插法中最后压入栈的元素在链表的开头,它的 next 指针指向前一个压入栈的元素,在弹出元素时就可以通过 next 指针遍历到前一个压入栈的元素从而让这个元素成为新的栈顶元素。
|
||
|
||
```java
|
||
public class ListStack<Item> implements MyStack<Item> {
|
||
|
||
private Node top = null;
|
||
private int N = 0;
|
||
|
||
|
||
private class Node {
|
||
Item item;
|
||
Node next;
|
||
}
|
||
|
||
|
||
@Override
|
||
public MyStack<Item> push(Item item) {
|
||
|
||
Node newTop = new Node();
|
||
|
||
newTop.item = item;
|
||
newTop.next = top;
|
||
|
||
top = newTop;
|
||
|
||
N++;
|
||
|
||
return this;
|
||
}
|
||
|
||
|
||
@Override
|
||
public Item pop() throws Exception {
|
||
|
||
if (isEmpty()) {
|
||
throw new Exception("stack is empty");
|
||
}
|
||
|
||
Item item = top.item;
|
||
|
||
top = top.next;
|
||
N--;
|
||
|
||
return item;
|
||
}
|
||
|
||
|
||
@Override
|
||
public boolean isEmpty() {
|
||
return N == 0;
|
||
}
|
||
|
||
|
||
@Override
|
||
public int size() {
|
||
return N;
|
||
}
|
||
|
||
|
||
@Override
|
||
public Iterator<Item> iterator() {
|
||
|
||
return new Iterator<Item>() {
|
||
|
||
private Node cur = top;
|
||
|
||
|
||
@Override
|
||
public boolean hasNext() {
|
||
return cur != null;
|
||
}
|
||
|
||
|
||
@Override
|
||
public Item next() {
|
||
Item item = cur.item;
|
||
cur = cur.next;
|
||
return item;
|
||
}
|
||
};
|
||
|
||
}
|
||
}
|
||
```
|
||
|
||
# 队列
|
||
|
||
下面是队列的链表实现,需要维护 first 和 last 节点指针,分别指向队首和队尾。
|
||
|
||
这里需要考虑 first 和 last 指针哪个作为链表的开头。因为出队列操作需要让队首元素的下一个元素成为队首,所以需要容易获取下一个元素,而链表的头部节点的 next 指针指向下一个元素,因此可以让 first 指针链表的开头。
|
||
|
||
```java
|
||
public interface MyQueue<Item> extends Iterable<Item> {
|
||
|
||
int size();
|
||
|
||
boolean isEmpty();
|
||
|
||
MyQueue<Item> add(Item item);
|
||
|
||
Item remove() throws Exception;
|
||
}
|
||
```
|
||
|
||
```java
|
||
public class ListQueue<Item> implements MyQueue<Item> {
|
||
|
||
private Node first;
|
||
private Node last;
|
||
int N = 0;
|
||
|
||
|
||
private class Node {
|
||
Item item;
|
||
Node next;
|
||
}
|
||
|
||
|
||
@Override
|
||
public boolean isEmpty() {
|
||
return N == 0;
|
||
}
|
||
|
||
|
||
@Override
|
||
public int size() {
|
||
return N;
|
||
}
|
||
|
||
|
||
@Override
|
||
public MyQueue<Item> add(Item item) {
|
||
|
||
Node newNode = new Node();
|
||
newNode.item = item;
|
||
newNode.next = null;
|
||
|
||
if (isEmpty()) {
|
||
last = newNode;
|
||
first = newNode;
|
||
} else {
|
||
last.next = newNode;
|
||
last = newNode;
|
||
}
|
||
|
||
N++;
|
||
return this;
|
||
}
|
||
|
||
|
||
@Override
|
||
public Item remove() throws Exception {
|
||
|
||
if (isEmpty()) {
|
||
throw new Exception("queue is empty");
|
||
}
|
||
|
||
Node node = first;
|
||
first = first.next;
|
||
N--;
|
||
|
||
if (isEmpty()) {
|
||
last = null;
|
||
}
|
||
|
||
return node.item;
|
||
}
|
||
|
||
|
||
@Override
|
||
public Iterator<Item> iterator() {
|
||
|
||
return new Iterator<Item>() {
|
||
|
||
Node cur = first;
|
||
|
||
|
||
@Override
|
||
public boolean hasNext() {
|
||
return cur != null;
|
||
}
|
||
|
||
|
||
@Override
|
||
public Item next() {
|
||
Item item = cur.item;
|
||
cur = cur.next;
|
||
return item;
|
||
}
|
||
};
|
||
}
|
||
}
|
||
```
|
||
|
||
|
||
|
||
|
||
</br><div align="center">公众号 CyC2018,专注于核心基础知识分享、求职指导、技术成长。在公众号后台回复 ziliao 可领取复习大纲,帮你理清复习重点。</div></br>
|
||
<div align="center"><img width="180px" src="https://cyc-1256109796.cos.ap-guangzhou.myqcloud.com/%E5%85%AC%E4%BC%97%E5%8F%B7.jpg"></img></div>
|