40 lines
1.1 KiB
Java
40 lines
1.1 KiB
Java
# 37. 序列化二叉树
|
||
|
||
[NowCoder](https://www.nowcoder.com/practice/cf7e25aa97c04cc1a68c8f040e71fb84?tpId=13&tqId=11214&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
|
||
|
||
## 题目描述
|
||
|
||
请实现两个函数,分别用来序列化和反序列化二叉树。
|
||
|
||
## 解题思路
|
||
|
||
```java
|
||
private String deserializeStr;
|
||
|
||
public String Serialize(TreeNode root) {
|
||
if (root == null)
|
||
return "#";
|
||
return root.val + " " + Serialize(root.left) + " " + Serialize(root.right);
|
||
}
|
||
|
||
public TreeNode Deserialize(String str) {
|
||
deserializeStr = str;
|
||
return Deserialize();
|
||
}
|
||
|
||
private TreeNode Deserialize() {
|
||
if (deserializeStr.length() == 0)
|
||
return null;
|
||
int index = deserializeStr.indexOf(" ");
|
||
String node = index == -1 ? deserializeStr : deserializeStr.substring(0, index);
|
||
deserializeStr = index == -1 ? "" : deserializeStr.substring(index + 1);
|
||
if (node.equals("#"))
|
||
return null;
|
||
int val = Integer.valueOf(node);
|
||
TreeNode t = new TreeNode(val);
|
||
t.left = Deserialize();
|
||
t.right = Deserialize();
|
||
return t;
|
||
}
|
||
```
|