I wish C++ didn't demand that functions have to appear before each other in lexographic order. =/

This commit is contained in:
ThePhD 2013-12-21 19:39:51 -05:00
parent b90f789986
commit ef223ecaeb

View File

@ -26,29 +26,6 @@
#include <type_traits>
namespace sol {
namespace detail {
template<typename T, bool isclass = std::is_class<Unqualified<T>>::value>
struct is_function_impl : std::is_function<typename std::remove_pointer<T>::type> { };
template<typename T>
struct is_function_impl<T, true> {
using yes = char;
using no = struct { char s[ 2 ]; };
struct F { void operator()( ); };
struct Derived : T, F { };
template<typename U, U> struct Check;
template<typename V>
static no test( Check<void ( F::* )( ), &V::operator()>* );
template<typename>
static yes test( ... );
static const bool value = sizeof( test<Derived>( 0 ) ) == sizeof( yes );
};
} // detail
template<typename T, typename R = void>
using EnableIf = typename std::enable_if<T::value, R>::type;
@ -78,6 +55,30 @@ struct multi_return<> : types<>{
template<bool B>
using Bool = std::integral_constant<bool, B>;
namespace detail {
template<typename T, bool isclass = std::is_class<Unqualified<T>>::value>
struct is_function_impl : std::is_function<typename std::remove_pointer<T>::type> { };
template<typename T>
struct is_function_impl<T, true> {
using yes = char;
using no = struct { char s[ 2 ]; };
struct F { void operator()( ); };
struct Derived : T, F { };
template<typename U, U> struct Check;
template<typename V>
static no test( Check<void ( F::* )( ), &V::operator()>* );
template<typename>
static yes test( ... );
static const bool value = sizeof( test<Derived>( 0 ) ) == sizeof( yes );
};
} // detail
template<typename T>
struct Function : Bool<detail::is_function_impl<T>::value> { };