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Why not cheat with an extra types
? Who needs type deduction when you can just pass the right types directly?
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@ -225,17 +225,17 @@ auto ltr_pop(lua_State* L, F&& f, types<Head, Tail...>, Vs&&... vs) -> decltype(
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return ltr_pop(L, std::forward<F>(f), types<Tail...>(), std::forward<Vs>(vs)..., pop<Head>(L));
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}
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template<typename F, typename... Vs>
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auto rtl_pop(lua_State*, F&& f, types<>, Vs&&... vs) -> decltype(f(std::forward<Vs>(vs)...)) {
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template<typename F, typename... Vs, typename... Args>
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auto rtl_pop(lua_State*, F&& f, types<Args...>, types<>, Vs&&... vs) -> decltype(f(std::forward<Vs>(vs)...)) {
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return f(std::forward<Vs>(vs)...);
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}
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template<typename F, typename Head, typename... Vs>
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auto rtl_pop(lua_State* L, F&& f, types<Head>, Vs&&... vs) -> decltype(rtl_pop(L, std::forward<F>(f), types<>(), pop<Head>(L), std::forward<Vs>(vs)...)) {
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return rtl_pop(L, std::forward<F>(f), types<>(), pop<Head>(L), std::forward<Vs>(vs)...);
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template<typename F, typename Head, typename... Vs, typename... Args>
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auto rtl_pop(lua_State* L, F&& f, types<Args...> t, types<Head>, Vs&&... vs) -> decltype(f(std::forward<Args>(std::declval<Args>())...)) {
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return rtl_pop(L, std::forward<F>(f), t, types<>(), pop<Head>(L), std::forward<Vs>(vs)...);
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}
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template<typename F, typename Head, typename... Tail, typename... Vs, typename... Args>
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auto rtl_pop(lua_State* L, F&& f, types<Args...>, types<Head, Tail...>, Vs&&... vs) -> decltype(f(std::forward<Args>(std::declval<Args>())...)) {
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return rtl_pop(L, std::forward<F>(f), types<Tail...>(), pop<Head>(L), std::forward<Vs>(vs)...);
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auto rtl_pop(lua_State* L, F&& f, types<Args...> t, types<Head, Tail...>, Vs&&... vs) -> decltype(f(std::forward<Args>(std::declval<Args>())...)) {
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return rtl_pop(L, std::forward<F>(f), t, types<Tail...>(), pop<Head>(L), std::forward<Vs>(vs)...);
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}
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} // detail
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