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Revert "feat(allowBlockIndents): Indented inline block elements can be parsed as markdown"

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This reverts commit f6326b84e4.
This commit is contained in:
Estevão Soares dos Santos 2015-01-17 00:13:12 +00:00
parent f6326b84e4
commit c9de4b6b1f
6 changed files with 1 additions and 64 deletions
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dist/showdown.js vendored
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src/showdown.js
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@ -6,8 +6,7 @@
var showdown = {},
parsers = {},
globalOptions = {
omitExtraWLInCodeBlocks: false,
allowBlockIndents: true
omitExtraWLInCodeBlocks: false
};
///////////////////////////////////////////////////////////////////////////

62
src/subParsers/allowBlockIndents.js
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@ -1,62 +0,0 @@
/**
* Credits to Christopher (https://github.com/cwalker107)
*/
/**
* If text is being pulled from indented HTML elements, i.e.
* <body>
* <div>
* ## Content to be converted
* </div>
* </body>
*/
showdown.subParser('allowBlockIndents', function (text, config, globals) {
'use strict';
if (!config.allowBlockIndents) {
return text;
}
//Split the given array by it's new line characters
var textSplitArr = text.split('\n');
//We'll use this later to determine if there are leading whitespace characters
var leadingWhiteChars = 0;
var i;
for(i=0; i<=textSplitArr.length;i++) {
if(textSplitArr[i] !== undefined) {
// Trim all trailing whitespaces from each line
textSplitArr[i].replace(/[\s]*$/,'');
// roots out empty array values
if(textSplitArr[i].length > 0) {
// Defines this single line's leading whitespace
var lineLeadingWhiteChars = (textSplitArr[i].match(/^(\s)*/))[0].length;
// Determine how much the text is indented
// by. This fixes nesting issues and also
// doesn't break MarkDown syntax if code is on
// the first lines
if(leadingWhiteChars === 0 || (lineLeadingWhiteChars < leadingWhiteChars)) {
if(textSplitArr[i].match(/[^\s]$/) !== null) {
leadingWhiteChars = lineLeadingWhiteChars;
}
}
}
}
}
// Only a regex that will replace how much it is indented by
var reg = '^\\s{'+leadingWhiteChars+'}';
for(i=0; i<=textSplitArr.length;i++) {
if(textSplitArr[i] !== undefined) {
// Replace leading indents
textSplitArr[i] = textSplitArr[i].replace(new RegExp(reg),'');
}
}
text = textSplitArr.join('\n\n'); //Join it all back together
return text;
});