0356380996
Fix `swarm_pair_factory`
94 lines
3.1 KiB
Python
94 lines
3.1 KiB
Python
import asyncio
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import pytest
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from libp2p.network.exceptions import SwarmException
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from tests.factories import ListeningSwarmFactory
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from tests.utils import connect_swarm
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@pytest.mark.asyncio
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async def test_swarm_dial_peer(is_host_secure):
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swarms = await ListeningSwarmFactory.create_batch_and_listen(is_host_secure, 3)
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# Test: No addr found.
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with pytest.raises(SwarmException):
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await swarms[0].dial_peer(swarms[1].get_peer_id())
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# Test: len(addr) in the peerstore is 0.
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swarms[0].peerstore.add_addrs(swarms[1].get_peer_id(), [], 10000)
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with pytest.raises(SwarmException):
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await swarms[0].dial_peer(swarms[1].get_peer_id())
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# Test: Succeed if addrs of the peer_id are present in the peerstore.
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addrs = tuple(
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addr
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for transport in swarms[1].listeners.values()
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for addr in transport.get_addrs()
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)
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swarms[0].peerstore.add_addrs(swarms[1].get_peer_id(), addrs, 10000)
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await swarms[0].dial_peer(swarms[1].get_peer_id())
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assert swarms[0].get_peer_id() in swarms[1].connections
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assert swarms[1].get_peer_id() in swarms[0].connections
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# Test: Reuse connections when we already have ones with a peer.
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conn_to_1 = swarms[0].connections[swarms[1].get_peer_id()]
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conn = await swarms[0].dial_peer(swarms[1].get_peer_id())
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assert conn is conn_to_1
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# Clean up
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await asyncio.gather(*[swarm.close() for swarm in swarms])
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@pytest.mark.asyncio
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async def test_swarm_close_peer(is_host_secure):
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swarms = await ListeningSwarmFactory.create_batch_and_listen(is_host_secure, 3)
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# 0 <> 1 <> 2
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await connect_swarm(swarms[0], swarms[1])
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await connect_swarm(swarms[1], swarms[2])
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# peer 1 closes peer 0
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await swarms[1].close_peer(swarms[0].get_peer_id())
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await asyncio.sleep(0.01)
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# 0 1 <> 2
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assert len(swarms[0].connections) == 0
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assert (
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len(swarms[1].connections) == 1
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and swarms[2].get_peer_id() in swarms[1].connections
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)
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# peer 1 is closed by peer 2
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await swarms[2].close_peer(swarms[1].get_peer_id())
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await asyncio.sleep(0.01)
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# 0 1 2
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assert len(swarms[1].connections) == 0 and len(swarms[2].connections) == 0
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await connect_swarm(swarms[0], swarms[1])
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# 0 <> 1 2
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assert (
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len(swarms[0].connections) == 1
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and swarms[1].get_peer_id() in swarms[0].connections
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)
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assert (
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len(swarms[1].connections) == 1
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and swarms[0].get_peer_id() in swarms[1].connections
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)
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# peer 0 closes peer 1
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await swarms[0].close_peer(swarms[1].get_peer_id())
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await asyncio.sleep(0.01)
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# 0 1 2
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assert len(swarms[1].connections) == 0 and len(swarms[2].connections) == 0
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# Clean up
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await asyncio.gather(*[swarm.close() for swarm in swarms])
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@pytest.mark.asyncio
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async def test_swarm_remove_conn(swarm_pair):
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swarm_0, swarm_1 = swarm_pair
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conn_0 = swarm_0.connections[swarm_1.get_peer_id()]
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swarm_0.remove_conn(conn_0)
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assert swarm_1.get_peer_id() not in swarm_0.connections
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# Test: Remove twice. There should not be errors.
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swarm_0.remove_conn(conn_0)
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assert swarm_1.get_peer_id() not in swarm_0.connections
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