interactive-coding-challenges/arrays-strings/reverse_string.ipynb

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"## Problem: Implement the function void Reverse(char* str)\n",
"\n",
"* [Clarifying Questions](#Clarifying-Questions)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
"* [Code](#Code)\n",
"* [Pythonic-Code](#Pythonic-Code)"
]
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{
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"source": [
"## Clarifying Questions\n",
"\n",
"* Based on the function signature, it seems you have to implement this in C/C++?\n",
" * Yes\n",
"* Can you use additional data structures?\n",
" * No"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
"* NULL input\n",
"* '' -> ''\n",
"* 'foo bar' -> 'rab oof'"
]
},
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"## Algorithm\n",
"\n",
"We'll want to keep two pointers:\n",
"* i is a pointer to the first char\n",
"* j is a pointer to the last char\n",
"\n",
"To get a pointer to the last char, we need to loop through all characters, take note of null terminator.\n",
"\n",
"* while i < j\n",
" * swap i and j\n",
"\n",
"Complexity:\n",
"* Time: O(n)\n",
"* Space: In-place\n",
"\n",
"Note:\n",
"* Instead of using i, you can use str instead, although this might not be as intuitive."
]
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"source": [
"## Code"
]
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"# %load reverse_string.cpp\n",
"#include <stdio.h>\n",
"\n",
"void Reverse(char* str) {\n",
" if (str) {\n",
" char* i = str;\t// first letter\n",
" char* j = str;\t// last letter\n",
" \n",
" // find the end of the string\n",
" while (*j) {\n",
" j++;\n",
" }\n",
" \n",
" // don't point to the null terminator\n",
" j--;\n",
" \n",
" char tmp;\n",
" \n",
" // swap chars to reverse the string\n",
" while (i < j) {\n",
" tmp = *i;\n",
" *i++ = *j;\n",
" *j-- = tmp;\n",
" }\n",
" }\n",
"}\n",
"\n",
"int main() {\n",
" char test0[] = \"\";\n",
" char test1[] = \"foo\";\n",
" Reverse(NULL);\n",
" Reverse(test0);\n",
" Reverse(test1);\n",
" printf(\"%s \\n\", test0);\n",
" printf(\"%s \\n\", test1);\n",
" return 0;\n",
"}"
]
},
{
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"metadata": {},
"source": [
"## Pythonic Code\n",
"\n",
"The following code is Pythonic, but requires using additional data structures as Python strings are immutable. You could use a bytearray or a list instead of a string to simulate manipulating an array of characters."
]
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"cell_type": "code",
"execution_count": null,
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"source": [
"def reverse_string_alt(string):\n",
" return string[::-1]\n",
"\n",
"def reverse_string_alt2(string):\n",
" return ''.join(reversed(string))"
]
}
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