interactive-coding-challenges/graphs_trees/bst/bst_challenge.ipynb
2016-08-14 08:20:06 -04:00

227 lines
5.4 KiB
Python

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"This notebook was prepared by [Donne Martin](https://github.com/donnemartin). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)."
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Challenge Notebook"
]
},
{
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"metadata": {},
"source": [
"## Problem: Implement a binary search tree with an insert method.\n",
"\n",
"* [Constraints](#Constraints)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
"* [Code](#Code)\n",
"* [Unit Test](#Unit-Test)"
]
},
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"source": [
"## Constraints\n",
"\n",
"* Can we insert None values?\n",
" * No\n",
"* Can we assume we are working with valid integers?\n",
" * Yes\n",
"* Can we assume all left descendents <= n < all right descendents?\n",
" * Yes\n",
"* For simplicity, can we use just a Node class without a wrapper Tree class?\n",
" * Yes\n",
"* Do we have to keep track of the parent nodes?\n",
" * This is optional\n",
"* Can we assume this fits in memory?\n",
" * Yes"
]
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"## Test Cases\n",
"\n",
"### Insert\n",
"\n",
"Insert will be tested through the following traversal:\n",
"\n",
"### In-Order Traversal\n",
"\n",
"* 5, 2, 8, 1, 3 -> 1, 2, 3, 5, 8\n",
"* 1, 2, 3, 4, 5 -> 1, 2, 3, 4, 5\n",
"\n",
"If the `root` input is `None`, return a tree with the only element being the new root node.\n",
"\n",
"You do not have to code the in-order traversal, it is part of the unit test."
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm\n",
"\n",
"Refer to the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/graphs_trees/bst/bst_solution.ipynb). If you are stuck and need a hint, the solution notebook's algorithm discussion might be a good place to start."
]
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"cell_type": "markdown",
"metadata": {},
"source": [
"## Code"
]
},
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"cell_type": "code",
"execution_count": null,
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"source": [
"class Node(object):\n",
"\n",
" def __init__(self, data):\n",
" # TODO: Implement me\n",
" pass\n",
"\n",
"\n",
"class Bst(object):\n",
"\n",
" def insert(self, data):\n",
" # TODO: Implement me\n",
" pass"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Unit Test"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"**The following unit test is expected to fail until you solve the challenge.**"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
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"outputs": [],
"source": [
"%run dfs.py"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
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"outputs": [],
"source": [
"%run ../utils/results.py"
]
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{
"cell_type": "code",
"execution_count": null,
"metadata": {
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"outputs": [],
"source": [
"# %load test_bst.py\n",
"from nose.tools import assert_equal\n",
"\n",
"\n",
"class TestTree(object):\n",
"\n",
" def __init__(self):\n",
" self.results = Results()\n",
"\n",
" def test_tree_one(self):\n",
" bst = Bst()\n",
" bst.insert(5)\n",
" bst.insert(2)\n",
" bst.insert(8)\n",
" bst.insert(1)\n",
" bst.insert(3)\n",
" in_order_traversal(bst.root, self.results.add_result)\n",
" assert_equal(str(self.results), '[1, 2, 3, 5, 8]')\n",
" self.results.clear_results()\n",
"\n",
" def test_tree_two(self):\n",
" bst = Bst()\n",
" bst.insert(1)\n",
" bst.insert(2)\n",
" bst.insert(3)\n",
" bst.insert(4)\n",
" bst.insert(5)\n",
" in_order_traversal(bst.root, self.results.add_result)\n",
" assert_equal(str(self.results), '[1, 2, 3, 4, 5]')\n",
"\n",
" print('Success: test_tree')\n",
"\n",
"\n",
"def main():\n",
" test = TestTree()\n",
" test.test_tree_one()\n",
" test.test_tree_two()\n",
"\n",
"\n",
"if __name__ == '__main__':\n",
" main()"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Solution Notebook\n",
"\n",
"Review the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/graphs_trees/bst/bst_solution.ipynb) for a discussion on algorithms and code solutions."
]
}
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