interactive-coding-challenges/arrays_strings/permutation/permutation_solution.ipynb

260 lines
7.0 KiB
Python

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"cell_type": "markdown",
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"source": [
"This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)."
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Solution Notebook"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Problem: Determine if a string is a permutation of another string.\n",
"\n",
"* [Constraints](#Constraints)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm: Compare Sorted Strings](#Algorithm:-Compare-Sorted-Strings)\n",
"* [Code: Compare Sorted Strings](#Code:-Compare-Sorted-Strings)\n",
"* [Algorithm: Hashmap Lookup](#Algorithm:-Hash-Map-Lookup)\n",
"* [Code: Hashmap Lookup](#Code:-Hash-Map-Lookup)\n",
"* [Unit Test](#Unit-Test)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Constraints\n",
"\n",
"* Can we assume the string is ASCII?\n",
" * Yes\n",
" * Note: Unicode strings could require special handling depending on your language\n",
"* Is whitespace important?\n",
" * Yes\n",
"* Is this case sensitive? 'Nib', 'bin' is not a match?\n",
" * Yes\n",
"* Can we use additional data structures?\n",
" * Yes\n",
"* Can we assume this fits in memory?\n",
" * Yes"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
"* One or more None inputs -> False\n",
"* One or more empty strings -> False\n",
"* 'Nib', 'bin' -> False\n",
"* 'act', 'cat' -> True\n",
"* 'a ct', 'ca t' -> True\n",
"* 'dog', 'doggo' -> False"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm: Compare Sorted Strings\n",
"\n",
"Permutations contain the same strings but in different orders. This approach could be slow for large strings due to sorting.\n",
"\n",
"* Sort both strings\n",
"* If both sorted strings are equal\n",
" * return True\n",
"* Else\n",
" * return False\n",
"\n",
"Complexity:\n",
"* Time: O(n log n) from the sort, in general\n",
"* Space: O(n)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code: Compare Sorted Strings"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {},
"outputs": [],
"source": [
"class Permutations(object):\n",
"\n",
" def is_permutation(self, str1, str2):\n",
" if str1 is None or str2 is None:\n",
" return False\n",
" return sorted(str1) == sorted(str2)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm: Hash Map Lookup\n",
"\n",
"We'll keep a hash map (dict) to keep track of characters we encounter. \n",
"\n",
"Steps:\n",
"* Scan each character\n",
"* For each character in each string:\n",
" * If the character does not exist in a hash map, add the character to a hash map\n",
" * Else, increment the character's count\n",
"* If the hash maps for each string are equal\n",
" * Return True\n",
"* Else\n",
" * Return False\n",
"\n",
"Notes:\n",
"* Since the characters are in ASCII, we could potentially use an array of size 128 (or 256 for extended ASCII), where each array index is equivalent to an ASCII value\n",
"* Instead of using two hash maps, you could use one hash map and increment character values based on the first string and decrement based on the second string\n",
"* You can short circuit if the lengths of each string are not equal, although len() in Python is generally O(1) unlike other languages like C where getting the length of a string is O(n)\n",
"\n",
"Complexity:\n",
"* Time: O(n)\n",
"* Space: O(n)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code: Hash Map Lookup"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {},
"outputs": [],
"source": [
"from collections import defaultdict\n",
"\n",
"\n",
"class PermutationsAlt(object):\n",
"\n",
" def is_permutation(self, str1, str2):\n",
" if str1 is None or str2 is None:\n",
" return False\n",
" if len(str1) != len(str2):\n",
" return False\n",
" unique_counts1 = defaultdict(int)\n",
" unique_counts2 = defaultdict(int)\n",
" for char in str1:\n",
" unique_counts1[char] += 1\n",
" for char in str2:\n",
" unique_counts2[char] += 1\n",
" return unique_counts1 == unique_counts2"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Unit Test"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Overwriting test_permutation_solution.py\n"
]
}
],
"source": [
"%%writefile test_permutation_solution.py\n",
"import unittest\n",
"\n",
"\n",
"class TestPermutation(unittest.TestCase):\n",
"\n",
" def test_permutation(self, func):\n",
" self.assertEqual(func(None, 'foo'), False)\n",
" self.assertEqual(func('', 'foo'), False)\n",
" self.assertEqual(func('Nib', 'bin'), False)\n",
" self.assertEqual(func('act', 'cat'), True)\n",
" self.assertEqual(func('a ct', 'ca t'), True)\n",
" self.assertEqual(func('dog', 'doggo'), False)\n",
" print('Success: test_permutation')\n",
"\n",
"\n",
"def main():\n",
" test = TestPermutation()\n",
" permutations = Permutations()\n",
" test.test_permutation(permutations.is_permutation)\n",
" try:\n",
" permutations_alt = PermutationsAlt()\n",
" test.test_permutation(permutations_alt.is_permutation)\n",
" except NameError:\n",
" # Alternate solutions are only defined\n",
" # in the solutions file\n",
" pass\n",
"\n",
"\n",
"if __name__ == '__main__':\n",
" main()"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Success: test_permutation\n",
"Success: test_permutation\n"
]
}
],
"source": [
"run -i test_permutation_solution.py"
]
}
],
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