mirror of
https://github.com/donnemartin/interactive-coding-challenges.git
synced 2024-03-22 13:11:13 +08:00
176 lines
4.2 KiB
Python
176 lines
4.2 KiB
Python
{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Challenge Notebook"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Problem: Implement fibonacci recursively, dynamically, and iteratively.\n",
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"\n",
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"* [Constraints](#Constraints)\n",
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"* [Test Cases](#Test-Cases)\n",
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"* [Algorithm](#Algorithm)\n",
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"* [Code](#Code)\n",
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"* [Unit Test](#Unit-Test)\n",
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"* [Solution Notebook](#Solution-Notebook)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Constraints\n",
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"\n",
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"* Does the sequence start at 0 or 1?\n",
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" * 0\n",
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"* Can we assume the inputs are valid non-negative ints?\n",
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" * Yes\n",
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"* Are you looking for a recursive or iterative solution?\n",
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" * Implement both\n",
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"* Can we assume this fits memory?\n",
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" * Yes"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Test Cases\n",
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"\n",
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"* n = 0 -> 0\n",
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"* n = 1 -> 1\n",
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"* n = 6 -> 8\n",
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"* Fib sequence: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34..."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Algorithm\n",
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"\n",
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"Refer to the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/recursion_dynamic/fibonacci/fibonacci_solution.ipynb). If you are stuck and need a hint, the solution notebook's algorithm discussion might be a good place to start."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Code"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {
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"collapsed": true
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},
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"outputs": [],
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"source": [
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"class Math(object):\n",
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"\n",
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" def fib_iterative(self, n):\n",
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" # TODO: Implement me\n",
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" pass\n",
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"\n",
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" def fib_recursive(self, n):\n",
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" # TODO: Implement me\n",
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" pass\n",
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"\n",
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" def fib_dynamic(self, n):\n",
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" # TODO: Implement me\n",
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" pass"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Unit Test\n",
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"\n",
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"\n",
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"\n",
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"**The following unit test is expected to fail until you solve the challenge.**"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"source": [
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"# %load test_fibonacci.py\n",
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"from nose.tools import assert_equal\n",
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"\n",
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"\n",
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"class TestFib(object):\n",
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"\n",
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" def test_fib(self, func):\n",
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" result = []\n",
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" expected = [0, 1, 1, 2, 3, 5, 8, 13, 21, 34]\n",
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" for i in range(len(expected)):\n",
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" result.append(func(i))\n",
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" assert_equal(result, expected)\n",
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" print('Success: test_fib')\n",
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"\n",
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"\n",
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"def main():\n",
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" test = TestFib()\n",
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" math = Math()\n",
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" test.test_fib(math.fib_recursive)\n",
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" test.test_fib(math.fib_dynamic)\n",
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" test.test_fib(math.fib_iterative)\n",
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"\n",
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"\n",
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"if __name__ == '__main__':\n",
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" main()"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Solution Notebook\n",
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"\n",
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"Review the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/recursion_dynamic/fibonacci/fibonacci_solution.ipynb) for a discussion on algorithms and code solutions."
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.5.0"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 0
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}
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