interactive-coding-challenges/recursion-dynamic/fibonacci.ipynb

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"<small><i>This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://bit.ly/code-notes).</i></small>"
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"## Problem: Implement fibonacci recursively, dynamically, and iteratively.\n",
"\n",
"* [Clarifying Questions](#Clarifying-Questions)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
"* [Code](#Code)\n",
"* [Pythonic-Code](#Pythonic-Code)"
]
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"## Clarifying Questions\n",
"\n",
"* None"
]
},
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"## Test Cases\n",
"\n",
"* n = 0\n",
"* n = 1\n",
"* n > 1"
]
},
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"## Algorithm\n",
"\n",
"* Fibonacci is as follows: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34...\n",
"* If n = 0 or 1, return n\n",
"* Else return fib(n-1) + fib(n+2)\n",
"\n",
"Complexity:\n",
"* Time: O(2^n) if recursive or iterative, O(n) if dynamic\n",
"* Space: O(n) if recursive, O(1) if iterative, O(1) if dynamic"
]
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"## Code"
]
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"num_items = 10"
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"def fib_recursive(n):\n",
" if n == 0 or n == 1:\n",
" return n\n",
" else:\n",
" return fib_recursive(n-1) + fib_recursive(n-2)\n",
"\n",
"for i in xrange(num_items):\n",
" print(fib_recursive(i))"
]
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"cache = [None] * (num_items + 1)\n",
"\n",
"def fib_dynamic(n):\n",
" if n == 0 or n == 1:\n",
" return n\n",
" if cache[n] != None:\n",
" return cache[n]\n",
" cache[n] = fib_dynamic(n-1) + fib_dynamic(n-2)\n",
" return cache[n]\n",
"\n",
"for i in xrange(num_items):\n",
" print(fib_dynamic(i))"
]
},
{
"cell_type": "code",
"execution_count": null,
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"collapsed": false
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"source": [
"def fib_iterative(n):\n",
" a = 0 \n",
" b = 1\n",
" for _ in xrange(n):\n",
" a, b = b, a + b\n",
" return a\n",
"\n",
"for i in xrange(num_items):\n",
" print(fib_iterative(i))"
]
}
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