mirror of
https://github.com/donnemartin/interactive-coding-challenges.git
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92 lines
2.1 KiB
Plaintext
92 lines
2.1 KiB
Plaintext
{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Problem: Utopian Tree\n",
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"\n",
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"From HackerRank: https://www.hackerrank.com/challenges/utopian-tree\n",
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"\n",
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"* [Algorithm](#Algorithm)\n",
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"* [Code](#Code)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Algorithm\n",
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"\n",
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"* If cycles is 0, return height of 1\n",
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"* For 1 to cycles:\n",
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" * If cycle is odd, double height\n",
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" * Else, increment height\n",
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"* Return height\n",
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"\n",
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"Complexity:\n",
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"* Time: O(n), where n is the number of cycles, for each cycle we perform a calculation\n",
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"* Space: O(1)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Code"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"source": [
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"# cycles = 0, print 1: base case\n",
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"# cycles = 1, print 2: i = 1: 1 * 2\n",
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"# cycles = 4, print 7: i = 1: 1 * 2, i = 2: 2 + 1, i = 3: 3 * 2, i = 4: 6 + 1\n",
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"def calc_utopian_tree_height(cycles):\n",
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" height = 1\n",
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" if cycles == 0:\n",
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" return height\n",
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" for i in xrange(1, cycles+1):\n",
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" if i % 2 == 1:\n",
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" height *= 2\n",
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" else:\n",
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" height += 1\n",
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" return height\n",
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"\n",
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"num_lines = int(raw_input())\n",
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"for i in range(0, num_lines):\n",
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" cycles = raw_input()\n",
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" cycles = int(cycles)\n",
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" res = calc_utopian_tree_height(cycles)\n",
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" print res"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 2",
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"language": "python",
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"name": "python2"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 2
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython2",
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"version": "2.7.9"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 0
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}
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