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    "## Problem: Add two numbers whose digits are stored in a linked list in reverse order.\n",
    "\n",
    "* [Clarifying Questions](#Clarifying-Questions)\n",
    "* [Test Cases](#Test-Cases)\n",
    "* [Algorithm](#Algorithm)\n",
    "* [Code](#Code)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Clarifying Questions\n",
    "\n",
    "* Do you expect the return to be in reverse order too?\n",
    "    * Yes\n",
    "* What if one of the inputs is NULL?\n",
    "    * Return NULL for an invalid operation"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Test Cases\n",
    "\n",
    "* Empty list(s)\n",
    "* Add values of different lengths\n",
    "    * Input 1: 6->5->None\n",
    "    * Input 2: 9->8->7\n",
    "    * Result: 5->4->8\n",
    "* Add values of same lengths\n",
    "    * Exercised from values of different lengths\n",
    "    * Done here for completeness"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Algorithm\n",
    "\n",
    "We could solve this with an iterative or a recursive algorithm, both are well suited for this exercise.  We'll use a recursive algorithm for practice with recursion.  Note this takes an extra space of O(m) where m is the recursion depth.\n",
    "\n",
    "* Test for error cases\n",
    "* Careful with adding if the lists differ\n",
    "    * Only add if a node is not NULL\n",
    "    * Alternatively, we could add trailing zeroes to the smaller list\n",
    "* Base case:\n",
    "    * if first and second lists are NULL AND carry is zero\n",
    "        * Return NULL\n",
    "* Recursive case:\n",
    "    * value = carry\n",
    "    * value += first.data + second.data\n",
    "    * remainder = value % 10\n",
    "    * new_carry = 1 if value >= 10, else 0\n",
    "    * Create a node with the remainder\n",
    "    * node.next = self.add(first.next, second.next, new_carry)\n",
    "    * Return node\n",
    "\n",
    "Complexity:\n",
    "* Time: O(n)\n",
    "* Space: O(n), extra space for result and recursion depth"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Code"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {
    "collapsed": true
   },
   "outputs": [],
   "source": [
    "%run linked_list.py"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": null,
   "metadata": {
    "collapsed": false
   },
   "outputs": [],
   "source": [
    "class MyLinkedList(LinkedList):\n",
    "    def __add__(self, first_node, second_node, carry):\n",
    "        if type(carry) != int and carry < 0:\n",
    "            raise ValueError('Invalid int argument: carry')\n",
    "        if first_node is None and second_node is None and carry == 0:\n",
    "            return None\n",
    "        value = carry\n",
    "        value += first_node.data if first_node is not None else 0\n",
    "        value += second_node.data if second_node is not None else 0\n",
    "        remainder = value % 10\n",
    "        new_carry = 1 if value >= 10 else 0\n",
    "        node = Node(remainder)\n",
    "        #import pdb; pdb.set_trace()\n",
    "        node.next = self.__add__(first_node.next if first_node is not None else None, \n",
    "                                 second_node.next if first_node is not None else None, \n",
    "                                 new_carry)\n",
    "        return node\n",
    "\n",
    "    def add(self, first_list, second_list):\n",
    "        if first_list is None or second_list is None:\n",
    "            return None\n",
    "        head = self.__add__(first_list.head, second_list.head, 0)\n",
    "        return MyLinkedList(head)"
   ]
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  {
   "cell_type": "code",
   "execution_count": null,
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   "source": [
    "print('Add values of different lengths')\n",
    "# Input 1: 6->5->None\n",
    "# Input 2: 9->8->7\n",
    "# Result: 5->4->8\n",
    "first_head = Node(6)\n",
    "first_list = MyLinkedList(first_head)\n",
    "first_list.append(5)\n",
    "second_head = Node(9)\n",
    "second_list = MyLinkedList(second_head)\n",
    "second_list.append(8)\n",
    "second_list.append(7)\n",
    "result = MyLinkedList().add(first_list, second_list)\n",
    "result.print_list()\n",
    "print('Add values of same lengths')\n",
    "# Input 1: 6->5->4\n",
    "# Input 2: 9->8->7\n",
    "# Result: 5->4->2->1\n",
    "first_head = Node(6)\n",
    "first_list = MyLinkedList(first_head)\n",
    "first_list.append(5)\n",
    "first_list.append(4)\n",
    "second_head = Node(9)\n",
    "second_list = MyLinkedList(second_head)\n",
    "second_list.append(8)\n",
    "second_list.append(7)\n",
    "result = MyLinkedList().add(first_list, second_list)\n",
    "result.print_list()\n",
    "print('Empty list(s)')\n",
    "result = MyLinkedList().add(None, None)\n",
    "result = MyLinkedList().add(first_head, None)\n",
    "result = MyLinkedList().add(None, second_head)"
   ]
  }
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