{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://bit.ly/code-notes)." ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Problem: Implement a function to reverse a string.\n", "\n", "* [Clarifying Questions](#Clarifying-Questions)\n", "* [Test Cases](#Test-Cases)\n", "* [Algorithm](#Algorithm)\n", "* [Code](#Code)\n", "* [Pythonic-Code](#Pythonic-Code)\n", "* [C Algorithm](C-Algorithm)\n", "* [C Code]()" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Clarifying Questions\n", "\n", "* Can I use the slice operator or the reversed function?\n", " * No\n", "* Since Python string are immutable, can I use a list instead?\n", " * Yes" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Test Cases\n", "\n", "* NULL input\n", "* '' -> ''\n", "* 'foo bar' -> 'rab oof'" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": false }, "outputs": [], "source": [ "from nose.tools import assert_equal\n", "\n", "class Test(object):\n", " def test_reversed(self, func):\n", " assert_equal(func(None), None)\n", " assert_equal(func(''), '')\n", " assert_equal(func('foo bar'), 'rab oof')\n", "\n", "def run_tests(func):\n", " test = Test()\n", " test.test_reversed(func)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Algorithm\n", "\n", "* Convert the string to a list\n", "* Iterate len(string)/2 times, starting with i = 0:\n", " * Swap i and len(string) - 1 - i\n", " * Sncrement i\n", "* Convert the list to a string and return it\n", "\n", "Complexity:\n", "* Time: O(n)\n", "* Space: O(n), additional space converting to/from a list" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Code" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": false }, "outputs": [], "source": [ "def reverse_string(string):\n", " if string is None:\n", " return None\n", " string_list = list(string)\n", " string_length = len(string_list)\n", " for i in xrange(string_length/2):\n", " string_list[i], string_list[string_length - 1 - i] = \\\n", " string_list[string_length - 1 - i], string_list[i]\n", " return ''.join(string_list)\n", "\n", "run_tests(reverse_string)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Pythonic-Code\n", "\n", "This question has an artificial constraint that prevented the use of the slice operator and the reversed method. For completeness, the solutions for these are provided below." ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": false }, "outputs": [], "source": [ "def reverse_string_alt(string):\n", " if string is None:\n", " return None\n", " return string[::-1]\n", "\n", "def reverse_string_alt2(string):\n", " if string is None:\n", " return None \n", " return ''.join(reversed(string))\n", "\n", "run_tests(reverse_string_alt)\n", "run_tests(reverse_string_alt2)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## C Algorithm\n", "\n", "This is a classic problem in C/C++\n", "\n", "We'll want to keep two pointers:\n", "* i is a pointer to the first char\n", "* j is a pointer to the last char\n", "\n", "To get a pointer to the last char, we need to loop through all characters, take note of null terminator.\n", "\n", "* while i < j\n", " * swap i and j\n", "\n", "Complexity:\n", "* Time: O(n)\n", "* Space: In-place\n", "\n", "Note:\n", "* Instead of using i, you can use str instead, although this might not be as intuitive." ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## C Code" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": false }, "outputs": [], "source": [ "# %load reverse_string.cpp\n", "#include \n", "\n", "void Reverse(char* str) {\n", " if (str) {\n", " char* i = str;\t// first letter\n", " char* j = str;\t// last letter\n", " \n", " // find the end of the string\n", " while (*j) {\n", " j++;\n", " }\n", " \n", " // don't point to the null terminator\n", " j--;\n", " \n", " char tmp;\n", " \n", " // swap chars to reverse the string\n", " while (i < j) {\n", " tmp = *i;\n", " *i++ = *j;\n", " *j-- = tmp;\n", " }\n", " }\n", "}\n", "\n", "int main() {\n", " char test0[] = \"\";\n", " char test1[] = \"foo\";\n", " Reverse(NULL);\n", " Reverse(test0);\n", " Reverse(test1);\n", " printf(\"%s \\n\", test0);\n", " printf(\"%s \\n\", test1);\n", " return 0;\n", "}" ] } ], "metadata": { "kernelspec": { "display_name": "Python 2", "language": "python", "name": "python2" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.10" } }, "nbformat": 4, "nbformat_minor": 0 }