mirror of
https://github.com/donnemartin/interactive-coding-challenges.git
synced 2024-03-22 13:11:13 +08:00
Add sub two challenge
This commit is contained in:
Donne Martin
parent
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commit
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0
math_probability/sub_two/__init__.py
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0
math_probability/sub_two/__init__.py
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167
math_probability/sub_two/sub_two_challenge.ipynb
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167
math_probability/sub_two/sub_two_challenge.ipynb
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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"This notebook was prepared by [Donne Martin](https://github.com/donnemartin). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Challenge Notebook"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Problem: Find the difference of two integers without using the + or - sign.\n",
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"\n",
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"* [Constraints](#Constraints)\n",
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"* [Test Cases](#Test-Cases)\n",
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"* [Algorithm](#Algorithm)\n",
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"* [Code](#Code)\n",
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"* [Unit Test](#Unit-Test)\n",
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"* [Solution Notebook](#Solution-Notebook)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Constraints\n",
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"\n",
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"* Can we assume the inputs are valid?\n",
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" * No, check for None\n",
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"* Can we assume this fits memory?\n",
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" * Yes"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Test Cases\n",
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"\n",
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"<pre>\n",
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"* None input -> TypeError\n",
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"* 7, 5 -> 2\n",
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"* -5, -7 -> 2\n",
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"* -5, 7 -> -12\n",
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"* 5, -7 -> 12\n",
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"</pre>"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Algorithm\n",
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"\n",
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"Refer to the [Solution Notebook](). If you are stuck and need a hint, the solution notebook's algorithm discussion might be a good place to start."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Code"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"source": [
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"class Solution(object):\n",
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"\n",
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" def sub_two(self, val):\n",
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" # TODO: Implement me\n",
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" pass"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Unit Test"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"**The following unit test is expected to fail until you solve the challenge.**"
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]
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},
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{
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"cell_type": "code",
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"execution_count": null,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"source": [
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"# %load test_sub_two.py\n",
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"from nose.tools import assert_equal, assert_raises\n",
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"\n",
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"\n",
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"class TestSubTwo(object):\n",
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"\n",
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" def test_sub_two(self):\n",
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" solution = Solution()\n",
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" assert_raises(TypeError, solution.sub_two, None)\n",
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" assert_equal(solution.sub_two(7, 5), 2)\n",
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" assert_equal(solution.sub_two(-5, -7), 2)\n",
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" assert_equal(solution.sub_two(-5, 7), -12)\n",
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" assert_equal(solution.sub_two(5, -7), 12)\n",
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" print('Success: test_sub_two')\n",
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"\n",
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"\n",
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"def main():\n",
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" test = TestSubTwo()\n",
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" test.test_sub_two()\n",
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"\n",
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"\n",
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"if __name__ == '__main__':\n",
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" main()"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Solution Notebook\n",
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"\n",
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"Review the [Solution Notebook]() for a discussion on algorithms and code solutions."
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.5.0"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 0
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}
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206
math_probability/sub_two/sub_two_solution.ipynb
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math_probability/sub_two/sub_two_solution.ipynb
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@ -0,0 +1,206 @@
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{
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"cells": [
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"This notebook was prepared by [Donne Martin](https://github.com/donnemartin). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)."
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"# Solution Notebook"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Problem: Find the difference of two integers without using the + or - sign.\n",
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"\n",
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"* [Constraints](#Constraints)\n",
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"* [Test Cases](#Test-Cases)\n",
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"* [Algorithm](#Algorithm)\n",
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"* [Code](#Code)\n",
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"* [Unit Test](#Unit-Test)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Constraints\n",
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"\n",
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"* Can we assume the inputs are valid?\n",
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" * No, check for None\n",
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"* Can we assume this fits memory?\n",
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" * Yes"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Test Cases\n",
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"\n",
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"<pre>\n",
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"* None input -> TypeError\n",
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"* 7, 5 -> 2\n",
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"* -5, -7 -> 2\n",
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"* -5, 7 -> -12\n",
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"* 5, -7 -> 12\n",
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"</pre>"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Algorithm\n",
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"\n",
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"We'll look at the following example, subtracting a and b:\n",
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"\n",
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"<pre>\n",
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"a 0110 = 6 \n",
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"b 0101 = 5\n",
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"</pre>\n",
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"\n",
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"First, subtract a and b, without worrying about the borrow (0-0=0, 0-1=1, 1-1=0):\n",
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"\n",
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"result = a ^ b = 0011\n",
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"\n",
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"Next, calculate the borrow (0-1=1). We'll need to left shift one to prepare for the next iteration when we move to the next most significant bit:\n",
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"\n",
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"~a = 1001\n",
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" b = 0101\n",
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"~a & b = 0001\n",
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"\n",
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"borrow = (~a&b) << 1 = 0010\n",
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"\n",
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"If the borrow is not zero, we'll need to subtract the borrow from the result. Recusively call the function, passing in result and borrow.\n",
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"\n",
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"Complexity:\n",
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"* Time: O(b), where b is the number of bits\n",
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"* Space: O(b), where b is the number of bits"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Code"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 1,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"source": [
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"class Solution(object):\n",
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"\n",
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" def sub_two(self, a, b):\n",
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" if a is None or b is None:\n",
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" raise TypeError('a or b cannot be None')\n",
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" result = a ^ b;\n",
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" borrow = (~a & b) << 1\n",
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" if borrow != 0:\n",
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" return self.sub_two(result, borrow)\n",
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" return result;"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Unit Test"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 2,
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"metadata": {
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"collapsed": false
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"Overwriting test_sub_two.py\n"
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]
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}
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],
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"source": [
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"%%writefile test_sub_two.py\n",
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"from nose.tools import assert_equal, assert_raises\n",
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"\n",
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"\n",
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"class TestSubTwo(object):\n",
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"\n",
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" def test_sub_two(self):\n",
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" solution = Solution()\n",
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" assert_raises(TypeError, solution.sub_two, None)\n",
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" assert_equal(solution.sub_two(7, 5), 2)\n",
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" assert_equal(solution.sub_two(-5, -7), 2)\n",
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" assert_equal(solution.sub_two(-5, 7), -12)\n",
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" assert_equal(solution.sub_two(5, -7), 12)\n",
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" print('Success: test_sub_two')\n",
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"\n",
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"\n",
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"def main():\n",
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" test = TestSubTwo()\n",
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" test.test_sub_two()\n",
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"\n",
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"\n",
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"if __name__ == '__main__':\n",
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" main()"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 3,
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"metadata": {
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"collapsed": false,
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"scrolled": true
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},
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"outputs": [
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{
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"name": "stdout",
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"output_type": "stream",
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"text": [
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"Success: test_sub_two\n"
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]
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}
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],
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"source": [
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"%run -i test_sub_two.py"
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]
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}
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],
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"metadata": {
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"kernelspec": {
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"display_name": "Python 3",
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"language": "python",
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"name": "python3"
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},
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"language_info": {
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"codemirror_mode": {
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"name": "ipython",
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"version": 3
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},
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"file_extension": ".py",
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"mimetype": "text/x-python",
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"name": "python",
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"nbconvert_exporter": "python",
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"pygments_lexer": "ipython3",
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"version": "3.5.0"
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}
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},
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"nbformat": 4,
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"nbformat_minor": 0
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}
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22
math_probability/sub_two/test_sub_two.py
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22
math_probability/sub_two/test_sub_two.py
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from nose.tools import assert_equal, assert_raises
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class TestSubTwo(object):
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def test_sub_two(self):
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solution = Solution()
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assert_raises(TypeError, solution.sub_two, None)
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assert_equal(solution.sub_two(7, 5), 2)
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assert_equal(solution.sub_two(-5, -7), 2)
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assert_equal(solution.sub_two(-5, 7), -12)
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assert_equal(solution.sub_two(5, -7), 12)
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print('Success: test_sub_two')
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def main():
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test = TestSubTwo()
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test.test_sub_two()
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if __name__ == '__main__':
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main()
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