Added notebook solving the following: Determine if a string s1 is a rotation of another string s2.

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Donne Martin 2015-05-07 19:59:28 -04:00
parent 69df72a803
commit e5ad1f468b

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"## Problem: Determine if a string s1 is a rotation of another string s2. Also write a function is_substring which you can only call once to determine whether a rotation occurs\n",
"\n",
"* [Clarifying Questions](#Clarifying-Questions)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
"* [Code](#Code)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Clarifying Questions\n",
"\n",
"* Is the string ASCII (extended)? Or Unicode?\n",
" * ASCII extended, which is 256 characters\n",
"* Can you use additional data structures? \n",
" * Yes\n",
"* Is this case sensitive?\n",
" * Yes"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
"* Any strings that differ in size results in False\n",
"* NULL, 'foo' -> False (any NULL results in False)\n",
"* ' ', 'foo' -> False\n",
"* ' ', ' ' -> True\n",
"* 'foobarbaz', 'barbazfoo' -> True"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm\n",
"\n",
"Using the following test case:\n",
"* s1 = 'barbazfoo'\n",
"* s2 = 'foobarbaz'\n",
"\n",
"We see that if we can use the given is_substring method if we take compare s2 with s1 + s1:\n",
"* s2 = 'foobarbaz'\n",
"* s3 = 'barbaz*foobarbaz*foo'\n",
"\n",
"Complexity:\n",
"* Time: O(n)\n",
"* Space: O(2n) of additional space for s3, which reduces to O(n)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": false
},
"outputs": [],
"source": [
"def is_substring(s1, s2):\n",
" return s1 in s2\n",
"\n",
"def is_rotation(s1, s2):\n",
" if s1 is None or s2 is None:\n",
" return False\n",
" if len(s1) != len(s2):\n",
" return False\n",
" s3 = s1 + s1\n",
" return is_substring(s2, s3)\n",
"\n",
"print(is_rotation('o', 'oo'))\n",
"print(is_rotation(None, 'foo'))\n",
"print(is_rotation('', 'foo'))\n",
"print(is_rotation('', ''))\n",
"print(is_rotation('foobarbaz', 'barbazfoo'))"
]
}
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