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Polish kth to last element challenge and solution

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Update algorithm discussion and solution.
This commit is contained in:
Donne Martin 2016-06-12 23:27:36 -04:00
parent 801e583762
commit 90f7505018
2 changed files with 28 additions and 31 deletions
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10
linked_lists/kth_to_last_elem/kth_to_last_elem_challenge.ipynb
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@ -175,21 +175,21 @@
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49
linked_lists/kth_to_last_elem/kth_to_last_elem_solution.ipynb
View File

@ -63,10 +63,10 @@
"source": [
"## Algorithm\n",
"\n",
"* Setup two pointers, current and previous\n",
"* Give current a headstart, incrementing it once if k = 1, twice if k = 2, ...\n",
"* Increment both pointers until current reaches the end\n",
"* Return the value of previous\n",
"* Setup two pointers, fast and slow\n",
"* Give fast a headstart, incrementing it once if k = 1, twice if k = 2, ...\n",
"* Increment both pointers until fast reaches the end\n",
"* Return the value of slow\n",
"\n",
"Complexity:\n",
"* Time: O(n)\n",
@ -103,26 +103,23 @@
"\n",
" def kth_to_last_elem(self, k):\n",
" if self.head is None:\n",
" return\n",
" if k >= len(self):\n",
" return\n",
" curr = self.head\n",
" prev = self.head\n",
" counter = 0\n",
" return None\n",
" fast = self.head\n",
" slow = self.head\n",
"\n",
" # Give current a headstart, incrementing it\n",
" # Give fast a headstart, incrementing it\n",
" # once for k = 1, twice for k = 2, etc\n",
" while counter < k:\n",
" curr = curr.next\n",
" counter += 1\n",
" if curr is None:\n",
" return\n",
" for _ in range(k):\n",
" fast = fast.next\n",
" # If k >= num elements, return None\n",
" if fast is None:\n",
" return None\n",
"\n",
" # Increment both pointers until current reaches the end\n",
" while curr.next is not None:\n",
" curr = curr.next\n",
" prev = prev.next\n",
" return prev.data"
" # Increment both pointers until fast reaches the end\n",
" while fast.next is not None:\n",
" fast = fast.next\n",
" slow = slow.next\n",
" return slow.data"
]
},
{
@ -212,21 +209,21 @@
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