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https://github.com/donnemartin/interactive-coding-challenges.git
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Added python solution to the following: Implement a function to reverse a string.
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@ -11,13 +11,15 @@
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"cell_type": "markdown",
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"cell_type": "markdown",
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"metadata": {},
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"metadata": {},
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"source": [
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"source": [
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"## Problem: Implement the function void Reverse(char* str)\n",
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"## Problem: Implement a function to reverse a string.\n",
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"\n",
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"\n",
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"* [Clarifying Questions](#Clarifying-Questions)\n",
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"* [Clarifying Questions](#Clarifying-Questions)\n",
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"* [Test Cases](#Test-Cases)\n",
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"* [Test Cases](#Test-Cases)\n",
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"* [Algorithm](#Algorithm)\n",
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"* [Algorithm](#Algorithm)\n",
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"* [Code](#Code)\n",
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"* [Code](#Code)\n",
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"* [Pythonic-Code: Not In-Place](#Pythonic-Code:-Not-In-Place)"
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"* [C Algorithm](C-Algorithm)\n",
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"* [C Code]()\n",
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"* [Pythonic-Code](#Pythonic-Code)"
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]
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]
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},
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},
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{
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{
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@ -26,10 +28,10 @@
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"source": [
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"source": [
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"## Clarifying Questions\n",
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"## Clarifying Questions\n",
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"\n",
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"\n",
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"* Based on the function signature, it seems you have to implement this in C/C++?\n",
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"* Can I use the slice operator or the reversed function?\n",
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" * Yes\n",
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" * No\n",
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"* Can you use additional data structures?\n",
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"* Since Python string are immutable, can I use a list instead?\n",
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" * No, do the operation in-place"
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" * Yes"
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]
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]
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},
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},
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{
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{
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@ -43,12 +45,80 @@
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"* 'foo bar' -> 'rab oof'"
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"* 'foo bar' -> 'rab oof'"
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]
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]
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},
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},
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{
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"cell_type": "code",
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"execution_count": 3,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"source": [
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"from nose.tools import assert_equal\n",
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"\n",
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"class Test(object):\n",
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" def test_reversed(self, func):\n",
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" assert_equal(func(None), None)\n",
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" assert_equal(func(''), '')\n",
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" assert_equal(func('foo bar'), 'rab oof')\n",
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"\n",
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"def run_tests(func):\n",
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" test = Test()\n",
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" test.test_reversed(func)"
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]
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},
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{
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{
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"cell_type": "markdown",
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"cell_type": "markdown",
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"metadata": {},
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"metadata": {},
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"source": [
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"source": [
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"## Algorithm\n",
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"## Algorithm\n",
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"\n",
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"\n",
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"* Convert the string to a list\n",
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"* Iterate len(string)/2 times, starting with i = 0:\n",
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" * Swap i and len(string) - 1 - i\n",
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" * Sncrement i\n",
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"* Convert the list to a string and return it\n",
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"\n",
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"Complexity:\n",
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"* Time: O(n)\n",
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"* Space: O(n), additional space converting to/from a list"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## Code"
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]
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},
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{
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"cell_type": "code",
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"execution_count": 4,
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"metadata": {
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"collapsed": false
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},
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"outputs": [],
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"source": [
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"def reverse_string(string):\n",
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" if string is None:\n",
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" return None\n",
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" string_list = list(string)\n",
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" string_length = len(string_list)\n",
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" for i in xrange(string_length/2):\n",
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" string_list[i], string_list[string_length - 1 - i] = \\\n",
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" string_list[string_length - 1 - i], string_list[i]\n",
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" return ''.join(string_list)\n",
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"\n",
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"run_tests(reverse_string)"
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]
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},
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{
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"cell_type": "markdown",
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"metadata": {},
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"source": [
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"## C Algorithm\n",
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"\n",
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"This is a classic problem in C/C++\n",
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"\n",
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"We'll want to keep two pointers:\n",
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"We'll want to keep two pointers:\n",
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"* i is a pointer to the first char\n",
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"* i is a pointer to the first char\n",
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"* j is a pointer to the last char\n",
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"* j is a pointer to the last char\n",
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@ -70,7 +140,7 @@
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"cell_type": "markdown",
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"cell_type": "markdown",
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"metadata": {},
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"metadata": {},
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"source": [
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"source": [
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"## Code"
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"## C Code"
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]
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]
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},
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},
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{
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{
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@ -124,24 +194,31 @@
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"cell_type": "markdown",
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"cell_type": "markdown",
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"metadata": {},
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"metadata": {},
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"source": [
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"source": [
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"## Pythonic-Code: Not In-Place\n",
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"## Pythonic-Code\n",
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"\n",
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"\n",
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"The following code is Pythonic, but requires using additional data structures as Python strings are immutable. You could use a bytearray or a list instead of a string to simulate manipulating an array of characters."
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"This question has an artificial constraint that prevented the use of the slice operator and the reversed method. For completeness, the solutions for these are provided below."
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]
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]
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},
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},
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{
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{
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"cell_type": "code",
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"cell_type": "code",
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"execution_count": null,
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"execution_count": 7,
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"metadata": {
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"metadata": {
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"collapsed": false
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"collapsed": false
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},
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},
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"outputs": [],
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"outputs": [],
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"source": [
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"source": [
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"def reverse_string_alt(string):\n",
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"def reverse_string_alt(string):\n",
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" if string is None:\n",
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" return None\n",
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" return string[::-1]\n",
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" return string[::-1]\n",
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"\n",
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"\n",
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"def reverse_string_alt2(string):\n",
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"def reverse_string_alt2(string):\n",
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" return ''.join(reversed(string))"
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" if string is None:\n",
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" return None \n",
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" return ''.join(reversed(string))\n",
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"\n",
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"run_tests(reverse_string_alt)\n",
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"run_tests(reverse_string_alt2)"
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]
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]
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}
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}
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],
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],
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