Added notebook solving the following: Find the kth to last element of a linked list.

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Donne Martin 2015-05-07 19:56:25 -04:00
parent 82d3f09478
commit 69df72a803
2 changed files with 169 additions and 0 deletions

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@ -16,6 +16,7 @@ Continually updated IPython Notebooks containing algorithms and data structures.
* [Linked list with insert, find, delete, and print methods](http://nbviewer.ipython.org/github/donnemartin/algorithms-data-structures/blob/master/linked-lists/linked-list.ipynb)
* [Remove duplicates from a linked list](http://nbviewer.ipython.org/github/donnemartin/algorithms-data-structures/blob/master/linked-lists/remove-duplicates.ipynb)
* [Find the kth to last element of a linked list](http://nbviewer.ipython.org/github/donnemartin/algorithms-data-structures/blob/master/linked-lists/kth-to-last-elem.ipynb)
## License

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@ -0,0 +1,168 @@
{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Problem: Find the kth to last element of a linked list\n",
"\n",
"* [Clarifying Questions](#Clarifying-Questions)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
"* [Code](#Code)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Clarifying Questions\n",
"\n",
"* Do we assume the linked list class already exists?\n",
" * No, create one\n",
"* Is k an integer?\n",
" * Yes\n",
"* If k = 0, does this return the last element?\n",
" * Yes\n",
"* What happens if k is greater than or equal to the length of the linked list?\n",
" * Return None\n",
"* Can you insert NULL values in the list?\n",
" * No\n",
"* Can use additional data structures?\n",
" * No"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
"* Empty list\n",
"* k is not an integer\n",
"* k is >= the length of the linked list\n",
"* One element, k = 0\n",
"* General case with many elements, k < length of linked list"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm\n",
"\n",
"* Check for edge cases above, returning None for errors\n",
"* Setup two pointers, current and previous\n",
"* Give current a headstart, incrementing it once for k = 1, twice for k = 2, etc\n",
"* Increment both pointers until current reaches the end\n",
"* Return the value of previous\n",
"\n",
"Complexity:\n",
"* Time: O(n)\n",
"* Space: In-place"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": false
},
"outputs": [],
"source": [
"class Node(object):\n",
" def __init__(self, data):\n",
" self.data = data\n",
" self.next = None\n",
" \n",
"class LinkedList(object):\n",
" def __init__(self, head):\n",
" self.head = head\n",
" \n",
" def __len__(self):\n",
" curr = self.head\n",
" counter = 0\n",
" while curr is not None:\n",
" counter += 1\n",
" curr = curr.next\n",
" return counter\n",
" \n",
" def kth_to_last_elem(self, k):\n",
" if self.head is None:\n",
" return\n",
" if type(k) != int:\n",
" return\n",
" if k >= len(self):\n",
" return\n",
" curr = self.head\n",
" prev = self.head\n",
" counter = 0\n",
" while counter < k:\n",
" curr = curr.next\n",
" counter += 1\n",
" if curr is None:\n",
" return\n",
" while curr.next is not None:\n",
" curr = curr.next\n",
" prev = prev.next\n",
" return prev.data\n",
" \n",
" def insert_to_front(self, data):\n",
" if data is None:\n",
" return\n",
" node = Node(data)\n",
" if self.head is None:\n",
" self.head = node\n",
" else:\n",
" node.next = self.head\n",
" self.head = node\n",
" \n",
"# Empty list\n",
"linked_list = LinkedList(None)\n",
"print(linked_list.kth_to_last_elem(0))\n",
"# k is not an integer\n",
"print(linked_list.kth_to_last_elem('a'))\n",
"# k is >= the length of the linked list\n",
"print(linked_list.kth_to_last_elem(100))\n",
"# One element, k = 0\n",
"head = Node(2)\n",
"linked_list = LinkedList(head)\n",
"print(linked_list.kth_to_last_elem(0))\n",
"# General case with many elements, k < length of linked list\n",
"linked_list.insert_to_front(1)\n",
"linked_list.insert_to_front(3)\n",
"linked_list.insert_to_front(5)\n",
"linked_list.insert_to_front(7)\n",
"print(linked_list.kth_to_last_elem(2))"
]
}
],
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"language": "python",
"name": "python2"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
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"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython2",
"version": "2.7.9"
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"nbformat": 4,
"nbformat_minor": 0
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