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" This notebook was prepared by [Donne Martin](https://github.com/donnemartin). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges). "
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" # Solution Notebook "
]
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" ## Problem: Implement a binary search tree with an insert method. \n " ,
" \n " ,
" * [Constraints](#Constraints) \n " ,
" * [Test Cases](#Test-Cases) \n " ,
" * [Algorithm](#Algorithm) \n " ,
" * [Code](#Code) \n " ,
" * [Unit Test](#Unit-Test) "
]
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" ## Constraints \n " ,
" \n " ,
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" * Can we insert None values? \n " ,
" * No \n " ,
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" * Can we assume we are working with valid integers? \n " ,
" * Yes \n " ,
" * Can we assume all left descendents <= n < all right descendents? \n " ,
" * Yes \n " ,
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" * Do we have to keep track of the parent nodes? \n " ,
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" * This is optional \n " ,
" * Can we assume this fits in memory? \n " ,
" * Yes "
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]
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" ## Test Cases \n " ,
" \n " ,
" ### Insert \n " ,
" \n " ,
" Insert will be tested through the following traversal: \n " ,
" \n " ,
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" ### In-Order Traversal \n " ,
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" \n " ,
" * 5, 2, 8, 1, 3 -> 1, 2, 3, 5, 8 \n " ,
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" * 1, 2, 3, 4, 5 -> 1, 2, 3, 4, 5 \n " ,
" \n " ,
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" If the `root` input is `None`, return a tree with the only element being the new root node. \n " ,
" \n " ,
" You do not have to code the in-order traversal, it is part of the unit test. "
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]
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" ## Algorithm \n " ,
" \n " ,
" ### Insert \n " ,
" \n " ,
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" * If the root is None, return Node(data) \n " ,
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" * If the data is <= the current node ' s data \n " ,
" * If the current node ' s left child is None, set it to Node(data) \n " ,
" * Else, recursively call insert on the left child \n " ,
" * Else \n " ,
" * If the current node ' s right child is None, set it to Node(data) \n " ,
" * Else, recursively call insert on the right child \n " ,
" \n " ,
" Complexity: \n " ,
" \n " ,
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" * Time: O(h), where h is the height of the tree \n " ,
" * In a balanced tree, the height is O(nlogn) \n " ,
" * In the worst case we have a linked list structure with O(n) \n " ,
" * Space: O(m), where m is the recursion depth, or O(1) if using an iterative approach "
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" ## Code "
]
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" cell_type " : " code " ,
" execution_count " : 1 ,
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" collapsed " : false
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" outputs " : [
{
" name " : " stdout " ,
" output_type " : " stream " ,
" text " : [
" Overwriting bst.py \n "
]
}
] ,
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" source " : [
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" %% writefile bst.py \n " ,
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" class Node(object): \n " ,
" \n " ,
" def __init__(self, data): \n " ,
" self.data = data \n " ,
" self.left = None \n " ,
" self.right = None \n " ,
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" self.parent = None \n " ,
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" \n " ,
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" def __repr__(self): \n " ,
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" return str(self.data) \n " ,
" \n " ,
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" \n " ,
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" class Bst(object): \n " ,
" \n " ,
" def __init__(self, root=None): \n " ,
" self.root = root \n " ,
" \n " ,
" def insert(self, data): \n " ,
" if data is None: \n " ,
" raise Exception( ' Data cannot be None ' ) \n " ,
" if self.root is None: \n " ,
" self.root = Node(data) \n " ,
" return self.root \n " ,
" return self._insert(self.root, data) \n " ,
" \n " ,
" def _insert(self, node, data): \n " ,
" # Constraint: Assume we are working with valid ints \n " ,
" if node is None: \n " ,
" return Node(data) \n " ,
" if data <= node.data: \n " ,
" if node.left is None: \n " ,
" node.left = self._insert(node.left, data) \n " ,
" node.left.parent = node \n " ,
" return node.left \n " ,
" else: \n " ,
" return self._insert(node.left, data) \n " ,
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" else: \n " ,
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" if node.right is None: \n " ,
" node.right = self._insert(node.right, data) \n " ,
" node.right.parent = node \n " ,
" return node.right \n " ,
" else: \n " ,
" return self._insert(node.right, data) "
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]
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" cell_type " : " code " ,
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" %r un bst.py "
]
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" ## Unit Test "
]
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" cell_type " : " code " ,
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" collapsed " : true
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" %r un dfs.py "
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" collapsed " : false
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" %r un ../utils/results.py "
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]
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" cell_type " : " code " ,
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" execution_count " : 5 ,
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" output_type " : " stream " ,
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" Overwriting test_bst.py \n "
]
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] ,
" source " : [
" %% writefile test_bst.py \n " ,
" from nose.tools import assert_equal \n " ,
" \n " ,
" \n " ,
" class TestTree(object): \n " ,
" \n " ,
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" def __init__(self): \n " ,
" self.results = Results() \n " ,
" \n " ,
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" def test_tree_one(self): \n " ,
" bst = Bst() \n " ,
" bst.insert(5) \n " ,
" bst.insert(2) \n " ,
" bst.insert(8) \n " ,
" bst.insert(1) \n " ,
" bst.insert(3) \n " ,
" in_order_traversal(bst.root, self.results.add_result) \n " ,
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" assert_equal(str(self.results), ' [1, 2, 3, 5, 8] ' ) \n " ,
" self.results.clear_results() \n " ,
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" \n " ,
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" def test_tree_two(self): \n " ,
" bst = Bst() \n " ,
" bst.insert(1) \n " ,
" bst.insert(2) \n " ,
" bst.insert(3) \n " ,
" bst.insert(4) \n " ,
" bst.insert(5) \n " ,
" in_order_traversal(bst.root, self.results.add_result) \n " ,
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" assert_equal(str(self.results), ' [1, 2, 3, 4, 5] ' ) \n " ,
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" \n " ,
" print( ' Success: test_tree ' ) \n " ,
" \n " ,
" \n " ,
" def main(): \n " ,
" test = TestTree() \n " ,
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" test.test_tree_one() \n " ,
" test.test_tree_two() \n " ,
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" \n " ,
" \n " ,
" if __name__ == ' __main__ ' : \n " ,
" main() "
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" name " : " stdout " ,
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" Success: test_tree \n "
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" %r un -i test_bst.py "
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