2017-03-28 17:13:55 +08:00
{
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" This notebook was prepared by [Donne Martin](https://github.com/donnemartin). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges). "
]
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" # Solution Notebook "
]
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" ## Problem: Find the highest product of three numbers in a list. \n " ,
" \n " ,
" * [Constraints](#Constraints) \n " ,
" * [Test Cases](#Test-Cases) \n " ,
" * [Algorithm](#Algorithm) \n " ,
" * [Code](#Code) \n " ,
" * [Unit Test](#Unit-Test) "
]
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{
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" ## Constraints \n " ,
" \n " ,
" * Is the input a list of integers? \n " ,
" * Yes \n " ,
" * Can we get negative inputs? \n " ,
" * Yes \n " ,
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" * Can there be duplicate entries in the input? \n " ,
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" * Yes \n " ,
" * Will there always be at least three integers? \n " ,
" * No \n " ,
" * Can we assume the inputs are valid? \n " ,
" * No, check for None input \n " ,
" * Can we assume this fits memory? \n " ,
" * Yes "
]
} ,
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" ## Test Cases \n " ,
" \n " ,
" * None -> TypeError \n " ,
" * Less than three ints -> ValueError \n " ,
" * [5, -2, 3] -> -30 \n " ,
" * [5, -2, 3, 1, -1, 4] -> 60 "
]
} ,
{
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" ## Algorithm \n " ,
" \n " ,
" ### Brute force: \n " ,
" \n " ,
" Use three loops and multiple each numbers. \n " ,
" \n " ,
" Complexity: \n " ,
" * Time: O(n^3) \n " ,
" * Space: O(1) \n " ,
" \n " ,
" ### Sorting: \n " ,
" \n " ,
" Sort the list, multiply the last three elements. \n " ,
" \n " ,
" Complexity: \n " ,
" * Time: O(n log(n)) \n " ,
" * Space: O(1) \n " ,
" \n " ,
" ### Greedy: \n " ,
" \n " ,
" <pre> \n " ,
" 0 1 2 3 4 5 \n " ,
" [5, -2, 3, 1, -1, 4] -> 60 \n " ,
" \n " ,
" max_prod_of_three = -30 \n " ,
" max_prod_of_two = -10 \n " ,
" max_num = 5 \n " ,
" min_prod_of_two = -10 \n " ,
" min_num = -2 \n " ,
" \n " ,
" 0 1 2 3 4 5 \n " ,
" [5, -2, 3, 1, -1, 4] -> 60 \n " ,
" ^ \n " ,
" max_prod_of_three = -30 \n " ,
" max_prod_of_two = 15 \n " ,
" max_num = 5 \n " ,
" min_prod_of_two = -10 \n " ,
" min_num = -2 \n " ,
" \n " ,
" 0 1 2 3 4 5 \n " ,
" [5, -2, 3, 1, -1, 4] -> 60 \n " ,
" ^ \n " ,
" max_prod_of_three = 15 \n " ,
" max_prod_of_two = 15 \n " ,
" max_num = 5 \n " ,
" min_prod_of_two = -10 \n " ,
" min_num = -2 \n " ,
" \n " ,
" 0 1 2 3 4 5 \n " ,
" [5, -2, 3, 1, -1, 4] -> 60 \n " ,
" ^ \n " ,
" max_prod_of_three = 15 \n " ,
" max_prod_of_two = 15 \n " ,
" max_num = 5 \n " ,
" min_prod_of_two = -10 \n " ,
" min_num = -2 \n " ,
" \n " ,
" 0 1 2 3 4 5 \n " ,
" [5, -2, 3, 1, -1, 4] -> 60 \n " ,
" ^ \n " ,
" max_prod_of_three = 60 \n " ,
" max_prod_of_two = 15 \n " ,
" max_num = 5 \n " ,
" min_prod_of_two = -10 \n " ,
" min_num = -2 \n " ,
" </pre> \n " ,
" \n " ,
" Complexity: \n " ,
" * Time: O(n) \n " ,
" * Space: O(1) "
]
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" ## Code "
]
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" cell_type " : " code " ,
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" class Solution(object): \n " ,
" \n " ,
" def max_prod_three_nlogn(self, array): \n " ,
" if array is None: \n " ,
" raise TypeError( ' array cannot be None ' ) \n " ,
" if len(array) < 3: \n " ,
" raise ValueError( ' array must have 3 or more ints ' ) \n " ,
" array.sort() \n " ,
" product = 1 \n " ,
" for item in array[-3:]: \n " ,
" product *= item \n " ,
" return product \n " ,
" \n " ,
" def max_prod_three(self, array): \n " ,
" if array is None: \n " ,
" raise TypeError( ' array cannot be None ' ) \n " ,
" if len(array) < 3: \n " ,
" raise ValueError( ' array must have 3 or more ints ' ) \n " ,
" curr_max_prod_three = array[0] * array[1] * array[2] \n " ,
" max_prod_two = array[0] * array[1] \n " ,
" min_prod_two = array[0] * array[1] \n " ,
" max_num = max(array[0], array[1]) \n " ,
" min_num = min(array[0], array[1]) \n " ,
" for i in range(2, len(array)): \n " ,
" curr_max_prod_three = max(curr_max_prod_three, \n " ,
" max_prod_two * array[i], \n " ,
" min_prod_two * array[i]) \n " ,
" max_prod_two = max(max_prod_two, \n " ,
" max_num * array[i], \n " ,
" min_num * array[i]) \n " ,
" min_prod_two = min(min_prod_two, \n " ,
" max_num * array[i], \n " ,
" min_num * array[i]) \n " ,
" max_num = max(max_num, array[i]) \n " ,
" min_num = min(min_num, array[i]) \n " ,
" return curr_max_prod_three "
]
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" ## Unit Test "
]
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" Overwriting test_prod_three.py \n "
]
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" source " : [
" %% writefile test_prod_three.py \n " ,
" from nose.tools import assert_equal, assert_raises \n " ,
" \n " ,
" \n " ,
" class TestProdThree(object): \n " ,
" \n " ,
" def test_prod_three(self): \n " ,
" solution = Solution() \n " ,
" assert_raises(TypeError, solution.max_prod_three, None) \n " ,
" assert_raises(ValueError, solution.max_prod_three, [1, 2]) \n " ,
" assert_equal(solution.max_prod_three([5, -2, 3]), -30) \n " ,
" assert_equal(solution.max_prod_three([5, -2, 3, 1, -1, 4]), 60) \n " ,
" print( ' Success: test_prod_three ' ) \n " ,
" \n " ,
" \n " ,
" def main(): \n " ,
" test = TestProdThree() \n " ,
" test.test_prod_three() \n " ,
" \n " ,
" \n " ,
" if __name__ == ' __main__ ' : \n " ,
" main() "
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" Success: test_prod_three \n "
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" %r un -i test_prod_three.py "
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