interactive-coding-challenges/graphs_trees/invert_tree/invert_tree_challenge.ipynb

201 lines
4.4 KiB
Python
Raw Normal View History

2017-03-30 17:39:30 +08:00
{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"This notebook was prepared by [Donne Martin](https://github.com/donnemartin). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)."
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Challenge Notebook"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Problem: Invert a binary tree.\n",
"\n",
"* [Constraints](#Constraints)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
"* [Code](#Code)\n",
"* [Unit Test](#Unit-Test)\n",
"* [Solution Notebook](#Solution-Notebook)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Constraints\n",
"\n",
"* What does it mean to invert a binary tree?\n",
" * Swap all left and right node pairs\n",
"* Can we assume we already have a Node class?\n",
" * Yes\n",
"* Can we assume the inputs are valid?\n",
" * No\n",
"* Can we assume this fits memory?\n",
" * Yes"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
"<pre>\n",
"Input:\n",
" 5\n",
" / \\\n",
" 2 7\n",
" / \\ / \\\n",
"1 3 6 9\n",
"\n",
"Output:\n",
" 5\n",
" / \\\n",
" 7 2\n",
" / \\ / \\\n",
"9 6 3 1\n",
"</pre>"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm\n",
"\n",
"Refer to the [Solution Notebook](). If you are stuck and need a hint, the solution notebook's algorithm discussion might be a good place to start."
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"%run ../bst/bst.py"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": false
},
"outputs": [],
"source": [
"class InverseBst(Bst):\n",
"\n",
" def invert_tree(self):\n",
" # TODO: Implement me\n",
" pass"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Unit Test"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"**The following unit test is expected to fail until you solve the challenge.**"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": false
},
"outputs": [],
"source": [
"# %load test_invert_tree.py\n",
"from nose.tools import assert_equal\n",
"\n",
"\n",
"class TestInvertTree(object):\n",
"\n",
" def test_invert_tree(self):\n",
" root = Node(5)\n",
" bst = InverseBst(root)\n",
" node2 = bst.insert(2)\n",
" node3 = bst.insert(3)\n",
" node1 = bst.insert(1)\n",
" node7 = bst.insert(7)\n",
" node6 = bst.insert(6)\n",
" node9 = bst.insert(9)\n",
" result = bst.invert_tree()\n",
" assert_equal(result, root)\n",
" assert_equal(result.left, node7)\n",
" assert_equal(result.right, node2)\n",
" assert_equal(result.left.left, node9)\n",
" assert_equal(result.left.right, node6)\n",
" assert_equal(result.right.left, node3)\n",
" assert_equal(result.right.right, node1)\n",
" print('Success: test_invert_tree')\n",
"\n",
"\n",
"def main():\n",
" test = TestInvertTree()\n",
" test.test_invert_tree()\n",
"\n",
"\n",
"if __name__ == '__main__':\n",
" main()"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Solution Notebook\n",
"\n",
"Review the [Solution Notebook]() for a discussion on algorithms and code solutions."
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Python 3",
"language": "python",
"name": "python3"
},
"language_info": {
"codemirror_mode": {
"name": "ipython",
"version": 3
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
"pygments_lexer": "ipython3",
"version": "3.5.0"
}
},
"nbformat": 4,
"nbformat_minor": 0
}