interactive-coding-challenges/arrays_strings/unique_chars/unique_chars_solution.ipynb

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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)."
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]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Solution Notebook"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Problem: Implement an algorithm to determine if a string has all unique characters.\n",
"\n",
"* [Constraints](#Constraints)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm 1: Sets and Length Comparison](#Algorithm-1:-Sets-and-Length-Comparison)\n",
"* [Code: Sets and Length Comparison](#Code:-Sets-and-Length-Comparison)\n",
"* [Algorithm 2: Hash Map Lookup](#Algorithm-2:-Hash-Map-Lookup)\n",
"* [Code: Hash Map Lookup](#Code:-Hash-Map-Lookup)\n",
"* [Algorithm 3: In-Place](#Algorithm-3:-In-Place)\n",
"* [Code: In-Place](#Code:-In-Place)\n",
"* [Unit Test](#Unit-Test)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Constraints\n",
"\n",
"* Can we assume the string is ASCII?\n",
" * Yes\n",
" * Note: Unicode strings could require special handling depending on your language\n",
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"* Can we assume this is case sensitive?\n",
" * Yes\n",
"* Can we use additional data structures?\n",
" * Yes\n",
"* Can we assume this fits in memory?\n",
" * Yes"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
"* None -> False\n",
"* '' -> True\n",
"* 'foo' -> False\n",
"* 'bar' -> True"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm 1: Sets and Length Comparison\n",
"\n",
"A set is an unordered collection of unique elements. \n",
"\n",
"* If the length of the set(string) equals the length of the string\n",
" * Return True\n",
"* Else\n",
" * Return False\n",
" \n",
"Complexity:\n",
"* Time: O(n)\n",
"* Space: Additional O(n)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code: Sets and Length Comparison"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"collapsed": false
},
"outputs": [],
"source": [
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"class UniqueCharsSet(object):\n",
"\n",
" def has_unique_chars(self, string):\n",
" if string is None:\n",
" return False\n",
" return len(set(string)) == len(string)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm 2: Hash Map Lookup\n",
"\n",
"We'll keep a hash map (set) to keep track of unique characters we encounter. \n",
"\n",
"Steps:\n",
"* Scan each character\n",
"* For each character:\n",
" * If the character does not exist in a hash map, add the character to a hash map\n",
" * Else, return False\n",
"* Return True\n",
"\n",
"Notes:\n",
"* We could also use a dictionary, but it seems more logical to use a set as it does not contain duplicate elements\n",
"* Since the characters are in ASCII, we could potentially use an array of size 128 (or 256 for extended ASCII)\n",
"\n",
"Complexity:\n",
"* Time: O(n)\n",
"* Space: Additional O(n)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code: Hash Map Lookup"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {
"collapsed": false
},
"outputs": [],
"source": [
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"class UniqueChars(object):\n",
"\n",
" def has_unique_chars(self, string):\n",
" if string is None:\n",
" return False\n",
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" chars_set = set()\n",
" for char in string:\n",
" if char in chars_set:\n",
" return False\n",
" else:\n",
" chars_set.add(char)\n",
" return True"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm 3: In-Place\n",
"\n",
"Assume we cannot use additional data structures, which will eliminate the fast lookup O(1) time provided by our hash map. \n",
"* Scan each character\n",
"* For each character:\n",
" * Scan all [other] characters in the array\n",
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" * Excluding the current character from the scan is rather tricky in Python and results in a non-Pythonic solution\n",
" * If there is a match, return False\n",
"* Return True\n",
"\n",
"Algorithm Complexity:\n",
"* Time: O(n^2)\n",
"* Space: O(1)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Code: In-Place"
]
},
{
"cell_type": "code",
"execution_count": 3,
"metadata": {
"collapsed": false
},
"outputs": [],
"source": [
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"class UniqueCharsInPlace(object):\n",
"\n",
" def has_unique_chars(self, string):\n",
" if string is None:\n",
" return False\n",
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" for char in string:\n",
" if string.count(char) > 1:\n",
" return False\n",
" return True"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Unit Test"
]
},
{
"cell_type": "code",
"execution_count": 4,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
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"Overwriting test_unique_chars.py\n"
]
}
],
"source": [
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"%%writefile test_unique_chars.py\n",
"from nose.tools import assert_equal\n",
"\n",
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"\n",
"class TestUniqueChars(object):\n",
"\n",
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" def test_unique_chars(self, func):\n",
" assert_equal(func(None), False)\n",
" assert_equal(func(''), True)\n",
" assert_equal(func('foo'), False)\n",
" assert_equal(func('bar'), True)\n",
" print('Success: test_unique_chars')\n",
"\n",
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"\n",
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"def main():\n",
" test = TestUniqueChars()\n",
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" unique_chars = UniqueChars()\n",
" test.test_unique_chars(unique_chars.has_unique_chars)\n",
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" try:\n",
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" unique_chars_set = UniqueCharsSet()\n",
" test.test_unique_chars(unique_chars_set.has_unique_chars)\n",
" unique_chars_in_place = UniqueCharsInPlace()\n",
" test.test_unique_chars(unique_chars_in_place.has_unique_chars)\n",
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" except NameError:\n",
" # Alternate solutions are only defined\n",
" # in the solutions file\n",
" pass\n",
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"\n",
"\n",
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"if __name__ == '__main__':\n",
" main()"
]
},
{
"cell_type": "code",
"execution_count": 5,
"metadata": {
"collapsed": false
},
"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
"Success: test_unique_chars\n",
"Success: test_unique_chars\n",
"Success: test_unique_chars\n"
]
}
],
"source": [
"%run -i test_unique_chars.py"
]
}
],
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"display_name": "Python 3",
"language": "python",
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