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" This notebook was prepared by [Donne Martin](https://github.com/donnemartin). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges). "
]
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{
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" # Solution Notebook "
]
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{
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" ## Problem: Find the single different char between two strings. \n " ,
" \n " ,
" * [Constraints](#Constraints) \n " ,
" * [Test Cases](#Test-Cases) \n " ,
" * [Algorithm](#Algorithm) \n " ,
" * [Code](#Code) \n " ,
" * [Unit Test](#Unit-Test) "
]
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{
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" ## Constraints \n " ,
" \n " ,
" * Can we assume the strings are ASCII? \n " ,
" * Yes \n " ,
" * Is case important? \n " ,
" * The strings are lower case \n " ,
" * Can we assume the inputs are valid? \n " ,
" * No, check for None \n " ,
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" * Otherwise, assume there is only a single different char between the two strings \n " ,
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" * Can we assume this fits memory? \n " ,
" * Yes "
]
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" ## Test Cases \n " ,
" \n " ,
" * None input -> TypeError \n " ,
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" * ' ab ' , ' aab ' -> ' a ' \n " ,
" * ' aab ' , ' ab ' -> ' a ' \n " ,
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" * ' abcd ' , ' abcde ' -> ' e ' \n " ,
" * ' aaabbcdd ' , ' abdbacade ' -> ' e ' "
]
} ,
{
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" ## Algorithm \n " ,
" \n " ,
" ### Dictionary \n " ,
" \n " ,
" * Keep a dictionary of seen values in s \n " ,
" * Loop through t, decrementing the seen values \n " ,
" * If the char is not there or if the decrement results in a negative value, return the char \n " ,
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" * Return the differing char from the dictionary \n " ,
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" \n " ,
" Complexity: \n " ,
" * Time: O(m+n), where m and n are the lengths of s, t \n " ,
" * Space: O(h), for the dict, where h is the unique chars in s \n " ,
" \n " ,
" ### XOR \n " ,
" \n " ,
" * XOR the two strings, which will isolate the differing char \n " ,
" \n " ,
" Complexity: \n " ,
" * Time: O(m+n), where m and n are the lengths of s, t \n " ,
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" * Space: O(1) "
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]
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" ## Code "
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" class Solution(object): \n " ,
" \n " ,
" def find_diff(self, str1, str2): \n " ,
" if str1 is None or str2 is None: \n " ,
" raise TypeError( ' str1 or str2 cannot be None ' ) \n " ,
" seen = {} \n " ,
" for char in str1: \n " ,
" if char in seen: \n " ,
" seen[char] += 1 \n " ,
" else: \n " ,
" seen[char] = 1 \n " ,
" for char in str2: \n " ,
" try: \n " ,
" seen[char] -= 1 \n " ,
" except KeyError: \n " ,
" return char \n " ,
" if seen[char] < 0: \n " ,
" return char \n " ,
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" for char, count in seen.items(): \n " ,
" return char \n " ,
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" \n " ,
" def find_diff_xor(self, str1, str2): \n " ,
" if str1 is None or str2 is None: \n " ,
" raise TypeError( ' str1 or str2 cannot be None ' ) \n " ,
" result = 0 \n " ,
" for char in str1: \n " ,
" result ^= ord(char) \n " ,
" for char in str2: \n " ,
" result ^= ord(char) \n " ,
" return chr(result) "
]
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" metadata " : { } ,
" source " : [
" ## Unit Test "
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" Overwriting test_str_diff.py \n "
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" source " : [
" %% writefile test_str_diff.py \n " ,
" from nose.tools import assert_equal, assert_raises \n " ,
" \n " ,
" \n " ,
" class TestFindDiff(object): \n " ,
" \n " ,
" def test_find_diff(self): \n " ,
" solution = Solution() \n " ,
" assert_raises(TypeError, solution.find_diff, None) \n " ,
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" assert_equal(solution.find_diff( ' ab ' , ' aab ' ), ' a ' ) \n " ,
" assert_equal(solution.find_diff( ' aab ' , ' ab ' ), ' a ' ) \n " ,
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" assert_equal(solution.find_diff( ' abcd ' , ' abcde ' ), ' e ' ) \n " ,
" assert_equal(solution.find_diff( ' aaabbcdd ' , ' abdbacade ' ), ' e ' ) \n " ,
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" assert_equal(solution.find_diff_xor( ' ab ' , ' aab ' ), ' a ' ) \n " ,
" assert_equal(solution.find_diff_xor( ' aab ' , ' ab ' ), ' a ' ) \n " ,
" assert_equal(solution.find_diff_xor( ' abcd ' , ' abcde ' ), ' e ' ) \n " ,
" assert_equal(solution.find_diff_xor( ' aaabbcdd ' , ' abdbacade ' ), ' e ' ) \n " ,
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" print( ' Success: test_find_diff ' ) \n " ,
" \n " ,
" \n " ,
" def main(): \n " ,
" test = TestFindDiff() \n " ,
" test.test_find_diff() \n " ,
" \n " ,
" \n " ,
" if __name__ == ' __main__ ' : \n " ,
" main() "
]
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" Success: test_find_diff \n "
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" %r un -i test_str_diff.py "
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