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" This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges). "
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" # Challenge Notebook "
]
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" ## Problem: Partition a linked list around a value x, such that all nodes less than x come before all nodes greater than or equal to x. \n " ,
" \n " ,
" * [Constraints](#Constraints) \n " ,
" * [Test Cases](#Test-Cases) \n " ,
" * [Algorithm](#Algorithm) \n " ,
" * [Code](#Code) \n " ,
" * [Unit Test](#Unit-Test) \n " ,
" * [Solution Notebook](#Solution-Notebook) "
]
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" ## Constraints \n " ,
" \n " ,
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" * Can we assume this is a non-circular, singly linked list? \n " ,
" * Yes \n " ,
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" * Do we expect the function to return a new list? \n " ,
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" * Yes \n " ,
" * Can we assume the input x is valid? \n " ,
" * Yes \n " ,
" * Can we assume we already have a linked list class that can be used for this problem? \n " ,
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" * Yes \n " ,
" * Can we create additional data structures? \n " ,
" * Yes \n " ,
" * Can we assume this fits in memory? \n " ,
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" * Yes "
]
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" ## Test Cases \n " ,
" \n " ,
" * Empty list -> [] \n " ,
" * One element list -> [element] \n " ,
" * Left linked list is empty \n " ,
" * Right linked list is empty \n " ,
" * General case \n " ,
" * Partition = 10 \n " ,
" * Input: 4, 3, 7, 8, 10, 1, 10, 12 \n " ,
" * Output: 4, 3, 7, 8, 1, 10, 10, 12 "
]
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" ## Algorithm \n " ,
" \n " ,
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" Refer to the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/linked_lists/partition/partition_solution.ipynb). If you are stuck and need a hint, the solution notebook ' s algorithm discussion might be a good place to start. "
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" ## Code "
]
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" cell_type " : " code " ,
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" collapsed " : true
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" source " : [
" %r un ../linked_list/linked_list.py \n " ,
" %lo ad ../linked_list/linked_list.py "
]
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" cell_type " : " code " ,
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" class MyLinkedList(LinkedList): \n " ,
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" \n " ,
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" def partition(self, data): \n " ,
" # TODO: Implement me \n " ,
" pass "
]
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" ## Unit Test "
]
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" \n " ,
" \n " ,
" **The following unit test is expected to fail until you solve the challenge.** "
]
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" # %lo ad test_partition.py \n " ,
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" import unittest \n " ,
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" \n " ,
" \n " ,
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" class TestPartition(unittest.TestCase): \n " ,
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" \n " ,
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" def test_partition(self): \n " ,
" print( ' Test: Empty list ' ) \n " ,
" linked_list = MyLinkedList(None) \n " ,
" linked_list.partition(10) \n " ,
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" self.assertEqual(linked_list.get_all_data(), []) \n " ,
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" \n " ,
" print( ' Test: One element list, left list empty ' ) \n " ,
" linked_list = MyLinkedList(Node(5)) \n " ,
" linked_list.partition(0) \n " ,
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" self.assertEqual(linked_list.get_all_data(), [5]) \n " ,
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" \n " ,
" print( ' Test: Right list is empty ' ) \n " ,
" linked_list = MyLinkedList(Node(5)) \n " ,
" linked_list.partition(10) \n " ,
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" self.assertEqual(linked_list.get_all_data(), [5]) \n " ,
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" \n " ,
" print( ' Test: General case ' ) \n " ,
" # Partition = 10 \n " ,
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" # Input: 4, 3, 13, 8, 10, 1, 14, 10, 12 \n " ,
" # Output: 4, 3, 8, 1, 10, 10, 13, 14, 12 \n " ,
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" linked_list = MyLinkedList(Node(12)) \n " ,
" linked_list.insert_to_front(10) \n " ,
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" linked_list.insert_to_front(14) \n " ,
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" linked_list.insert_to_front(1) \n " ,
" linked_list.insert_to_front(10) \n " ,
" linked_list.insert_to_front(8) \n " ,
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" linked_list.insert_to_front(13) \n " ,
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" linked_list.insert_to_front(3) \n " ,
" linked_list.insert_to_front(4) \n " ,
" partitioned_list = linked_list.partition(10) \n " ,
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" self.assertEqual(partitioned_list.get_all_data(), \n " ,
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" [4, 3, 8, 1, 10, 10, 13, 14, 12]) \n " ,
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" \n " ,
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" print( ' Success: test_partition ' ) \n " ,
" \n " ,
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" \n " ,
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" def main(): \n " ,
" test = TestPartition() \n " ,
" test.test_partition() \n " ,
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" \n " ,
" \n " ,
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" if __name__ == ' __main__ ' : \n " ,
" main() "
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" ## Solution Notebook \n " ,
" \n " ,
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" Review the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/linked_lists/partition/partition_solution.ipynb) for a discussion on algorithms and code solutions. "
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