interactive-coding-challenges/recursion_dynamic/fibonacci/fibonacci_solution.ipynb

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{
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"This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges)."
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]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Solution Notebook"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Problem: Implement fibonacci recursively, dynamically, and iteratively.\n",
"\n",
"* [Constraints](#Constraints)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
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"* [Code](#Code)\n",
"* [Unit Test](#Unit-Test)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Constraints\n",
"\n",
"* Does the sequence start at 0 or 1?\n",
" * 0\n",
"* Can we assume the inputs are valid non-negative ints?\n",
" * Yes\n",
"* Are you looking for a recursive or iterative solution?\n",
" * Either\n",
"* Can we assume this fits memory?\n",
" * Yes"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
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"* n = 0 -> 0\n",
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"* n = 1 -> 1\n",
"* n = 6 -> 8\n",
"* Fib sequence: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34..."
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Algorithm\n",
"\n",
"Recursive:\n",
"* Fibonacci is as follows: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34...\n",
"* If n = 0 or 1, return n\n",
"* Else return fib(n-1) + fib(n+2)\n",
"\n",
"Complexity:\n",
"* Time: O(2^n) if recursive or iterative, O(n) if dynamic\n",
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"* Space: O(n) if recursive, O(1) if iterative, O(n) if dynamic"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
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"## Code"
]
},
{
"cell_type": "code",
"execution_count": 1,
"metadata": {
"collapsed": true
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"outputs": [],
"source": [
"class Math(object):\n",
"\n",
" def fib_iterative(self, n):\n",
" a = 0\n",
" b = 1\n",
" for _ in range(n):\n",
" a, b = b, a + b\n",
" return a\n",
"\n",
" def fib_recursive(self, n):\n",
" if n == 0 or n == 1:\n",
" return n\n",
" else:\n",
" return self.fib_recursive(n-1) + self.fib_recursive(n-2)\n",
"\n",
" def fib_dynamic(self, n):\n",
" cache = {}\n",
" return self._fib_dynamic(n, cache)\n",
"\n",
" def _fib_dynamic(self, n, cache):\n",
" if n == 0 or n == 1:\n",
" return n\n",
" if n in cache:\n",
" return cache[n]\n",
" cache[n] = self._fib_dynamic(n-1, cache) + self._fib_dynamic(n-2, cache)\n",
" return cache[n]"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Unit Test\n",
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"\n"
]
},
{
"cell_type": "code",
"execution_count": 2,
"metadata": {
"collapsed": false
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"outputs": [
{
"name": "stdout",
"output_type": "stream",
"text": [
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"Overwriting test_fibonacci.py\n"
]
}
],
"source": [
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"%%writefile test_fibonacci.py\n",
"from nose.tools import assert_equal\n",
"\n",
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"\n",
"class TestFib(object):\n",
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"\n",
" def test_fib(self, func):\n",
" result = []\n",
" expected = [0, 1, 1, 2, 3, 5, 8, 13, 21, 34]\n",
" for i in range(len(expected)):\n",
" result.append(func(i))\n",
" assert_equal(result, expected)\n",
" print('Success: test_fib')\n",
"\n",
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"\n",
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"def main():\n",
" test = TestFib()\n",
" math = Math()\n",
" test.test_fib(math.fib_recursive)\n",
" test.test_fib(math.fib_dynamic)\n",
" test.test_fib(math.fib_iterative)\n",
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"\n",
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"\n",
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"if __name__ == '__main__':\n",
" main()"
]
},
{
"cell_type": "code",
"execution_count": 3,
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"metadata": {
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{
"name": "stdout",
"output_type": "stream",
"text": [
"Success: test_fib\n",
"Success: test_fib\n",
"Success: test_fib\n"
]
}
],
"source": [
"%run -i test_fibonacci.py"
]
}
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