interactive-coding-challenges/stacks-queues/stack.ipynb

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"## Problem: Implement a stack with push, pop, and peek methods using a linked list.\n",
"\n",
"* [Clarifying Questions](#Clarifying-Questions)\n",
"* [Test Cases](#Test-Cases)\n",
"* [Algorithm](#Algorithm)\n",
"* [Code](#Code)\n",
"* [Pythonic-Code](#Pythonic-Code)"
]
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"cell_type": "markdown",
"metadata": {},
"source": [
"## Clarifying Questions\n",
"\n",
"* None"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Test Cases\n",
"\n",
"### Push\n",
"\n",
"* Push to empty stack\n",
"* Push to non-empty stack\n",
"\n",
"### Pop\n",
"\n",
"* Pop on empty stack\n",
"* Pop on single element stack\n",
"* Pop on multiple element stack\n",
"\n",
"### Peek\n",
"\n",
"* Peek on empty stack\n",
"* Peek on one or more element stack"
]
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"## Algorithm\n",
"\n",
"### Push\n",
"\n",
"* Create new node with value\n",
"* Set node's next to top\n",
"* Set top to node\n",
"\n",
"Complexity:\n",
"* Time: O(1)\n",
"* Space: O(1)\n",
"\n",
"### Pop\n",
"\n",
"* If stack is empty, return NULL\n",
"* Else \n",
" * Save top's value\n",
" * Set top to top.next\n",
" * Return saved value\n",
"\n",
"Complexity:\n",
"* Time: O(1)\n",
"* Space: O(1)\n",
"\n",
"### Peek\n",
"\n",
"* If stack is empty, return NULL\n",
"* Else return top's value\n",
"\n",
"Complexity:\n",
"* Time: O(1)\n",
"* Space: O(1)"
]
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"cell_type": "markdown",
"metadata": {},
"source": [
"## Code"
]
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"%%writefile stack.py\n",
"\n",
"class Node(object):\n",
" def __init__(self, data):\n",
" self.data = data\n",
" self.next = None\n",
"\n",
"class Stack(object):\n",
" def __init__(self, top=None):\n",
" self.top = top\n",
"\n",
" def push(self, data):\n",
" node = Node(data)\n",
" node.next = self.top\n",
" self.top = node\n",
"\n",
" def pop(self):\n",
" if self.top is not None:\n",
" data = self.top.data\n",
" self.top = self.top.next\n",
" return data\n",
" return None\n",
"\n",
" def peek(self):\n",
" if self.top is not None:\n",
" return self.top.data\n",
" return None"
]
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{
"cell_type": "code",
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"source": [
"%run stack.py"
]
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"source": [
"print('Empty stack')\n",
"stack = Stack()\n",
"print(stack.peek())\n",
"print(stack.pop())\n",
"print('One element')\n",
"top = Node(5)\n",
"stack = Stack(top)\n",
"print(stack.pop())\n",
"print(stack.peek())\n",
"print('More than one element')\n",
"stack = Stack()\n",
"stack.push(1)\n",
"stack.push(2)\n",
"stack.push(3)\n",
"print(stack.pop())\n",
"print(stack.peek())\n",
"print(stack.pop())\n",
"print(stack.peek())\n",
"print(stack.pop())\n",
"print(stack.peek())"
]
},
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"cell_type": "markdown",
"metadata": {},
"source": [
"## Pythonic-Code"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"Source: https://docs.python.org/2/tutorial/datastructures.html#using-lists-as-stacks\n",
"<pre>\n",
"5.1.1. Using Lists as Stacks\n",
"The list methods make it very easy to use a list as a stack, where the last element added is the first element retrieved (“last-in, first-out”). To add an item to the top of the stack, use append(). To retrieve an item from the top of the stack, use pop() without an explicit index. For example:\n",
"\n",
">>> stack = [3, 4, 5]\n",
">>> stack.append(6)\n",
">>> stack.append(7)\n",
">>> stack\n",
"[3, 4, 5, 6, 7]\n",
">>> stack.pop()\n",
"7\n",
">>> stack\n",
"[3, 4, 5, 6]\n",
">>> stack.pop()\n",
"6\n",
">>> stack.pop()\n",
"5\n",
">>> stack\n",
"[3, 4]\n",
"</pre>"
]
}
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