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" This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges). "
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" # Solution Notebook "
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" ## Problem: Implement an algorithm to determine if a string has all unique characters \n " ,
" \n " ,
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" * [Constraints](#Constraints) \n " ,
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" * [Test Cases](#Test-Cases) \n " ,
" * [Algorithm 1: Sets and Length Comparison](#Algorithm-1:-Sets-and-Length-Comparison) \n " ,
" * [Code: Sets and Length Comparison](#Code:-Sets-and-Length-Comparison) \n " ,
" * [Algorithm 2: Hash Map Lookup](#Algorithm-2:-Hash-Map-Lookup) \n " ,
" * [Code: Hash Map Lookup](#Code:-Hash-Map-Lookup) \n " ,
" * [Algorithm 3: In-Place](#Algorithm-3:-In-Place) \n " ,
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" * [Code: In-Place](#Code:-In-Place) \n " ,
" * [Unit Test](#Unit-Test) "
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" ## Constraints \n " ,
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" \n " ,
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" * Can we assume the string is ASCII? \n " ,
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" * Yes \n " ,
" * Note: Unicode strings could require special handling depending on your language \n " ,
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" * Can we assume this is case sensitive? \n " ,
" * Yes \n " ,
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" * Can we use additional data structures? \n " ,
" * Yes \n " ,
" * Can we assume this fits in memory? \n " ,
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" * Yes "
]
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" ## Test Cases \n " ,
" \n " ,
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" * None -> False \n " ,
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" * ' ' -> True \n " ,
" * ' foo ' -> False \n " ,
" * ' bar ' -> True "
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]
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" ## Algorithm 1: Sets and Length Comparison \n " ,
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" \n " ,
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" A set is an unordered collection of unique elements. \n " ,
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" \n " ,
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" * If the length of the set(string) equals the length of the string \n " ,
" * Return True \n " ,
" * Else \n " ,
" * Return False \n " ,
" \n " ,
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" Complexity: \n " ,
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" * Time: O(n) \n " ,
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" * Space: Additional O(n) "
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]
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" ## Code: Sets and Length Comparison "
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" def unique_chars(string): \n " ,
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" if string is None: \n " ,
" return False \n " ,
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" return len(set(string)) == len(string) "
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]
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" ## Algorithm 2: Hash Map Lookup \n " ,
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" \n " ,
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" We ' ll keep a hash map (set) to keep track of unique characters we encounter. \n " ,
" \n " ,
" Steps: \n " ,
" * Scan each character \n " ,
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" * For each character: \n " ,
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" * If the character does not exist in a hash map, add the character to a hash map \n " ,
" * Else, return False \n " ,
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" * Return True \n " ,
" \n " ,
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" Notes: \n " ,
" * We could also use a dictionary, but it seems more logical to use a set as it does not contain duplicate elements \n " ,
" * Since the characters are in ASCII, we could potentially use an array of size 128 (or 256 for extended ASCII) \n " ,
" \n " ,
" Complexity: \n " ,
" * Time: O(n) \n " ,
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" * Space: Additional O(n) "
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]
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" ## Code: Hash Map Lookup "
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]
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" def unique_chars_hash(string): \n " ,
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" if string is None: \n " ,
" return False \n " ,
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" chars_set = set() \n " ,
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" for char in string: \n " ,
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" if char in chars_set: \n " ,
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" return False \n " ,
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" else: \n " ,
" chars_set.add(char) \n " ,
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" return True "
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]
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" ## Algorithm 3: In-Place \n " ,
" \n " ,
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" Assume we cannot use additional data structures, which will eliminate the fast lookup O(1) time provided by our hash map. \n " ,
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" * Scan each character \n " ,
" * For each character: \n " ,
" * Scan all [other] characters in the array \n " ,
" * Exluding the current character from the scan is rather tricky in Python and results in a non-Pythonic solution \n " ,
" * If there is a match, return False \n " ,
" * Return True \n " ,
" \n " ,
" Algorithm Complexity: \n " ,
" * Time: O(n^2) \n " ,
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" * Space: O(1) "
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]
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" ## Code: In-Place "
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]
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" execution_count " : 3 ,
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" def unique_chars_inplace(string): \n " ,
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" if string is None: \n " ,
" return False \n " ,
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" for char in string: \n " ,
" if string.count(char) > 1: \n " ,
" return False \n " ,
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" return True "
]
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" ## Unit Test "
]
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" text " : [
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" Overwriting test_unique_chars.py \n "
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]
}
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" source " : [
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" %% writefile test_unique_chars.py \n " ,
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" from nose.tools import assert_equal \n " ,
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" \n " ,
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" \n " ,
" class TestUniqueChars(object): \n " ,
" \n " ,
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" def test_unique_chars(self, func): \n " ,
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" assert_equal(func(None), False) \n " ,
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" assert_equal(func( ' ' ), True) \n " ,
" assert_equal(func( ' foo ' ), False) \n " ,
" assert_equal(func( ' bar ' ), True) \n " ,
" print( ' Success: test_unique_chars ' ) \n " ,
" \n " ,
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" \n " ,
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" def main(): \n " ,
" test = TestUniqueChars() \n " ,
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" test.test_unique_chars(unique_chars) \n " ,
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" try: \n " ,
" test.test_unique_chars(unique_chars_hash) \n " ,
" test.test_unique_chars(unique_chars_inplace) \n " ,
" except NameError: \n " ,
" # Alternate solutions are only defined \n " ,
" # in the solutions file \n " ,
" pass \n " ,
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" \n " ,
" \n " ,
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" if __name__ == ' __main__ ' : \n " ,
" main() "
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" Success: test_unique_chars \n " ,
" Success: test_unique_chars \n " ,
" Success: test_unique_chars \n "
]
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" %r un -i test_unique_chars.py "
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