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" This notebook was prepared by [Donne Martin](http://donnemartin.com). Source and license info is on [GitHub](https://github.com/donnemartin/interactive-coding-challenges). "
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]
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" # Challenge Notebook "
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]
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" ## Problem: Determine if a linked list is a palindrome. \n " ,
" \n " ,
" * [Constraints](#Constraints) \n " ,
" * [Test Cases](#Test-Cases) \n " ,
" * [Algorithm](#Algorithm) \n " ,
" * [Code](#Code) \n " ,
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" * [Unit Test](#Unit-Test) \n " ,
" * [Solution Notebook](#Solution-Notebook) "
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]
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" ## Constraints \n " ,
" \n " ,
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" * Can we assume this is a non-circular, singly linked list? \n " ,
" * Yes \n " ,
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" * Is a single character or number a palindrome? \n " ,
" * No \n " ,
" * Can we assume we already have a linked list class that can be used for this problem? \n " ,
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" * Yes \n " ,
" * Can we use additional data structures? \n " ,
" * Yes \n " ,
" * Can we assume this fits in memory? \n " ,
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" * Yes "
]
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" ## Test Cases \n " ,
" \n " ,
" \n " ,
" * Empty list -> False \n " ,
" * Single element list -> False \n " ,
" * Two or more element list, not a palindrome -> False \n " ,
" * General case: Palindrome with even length -> True \n " ,
" * General case: Palindrome with odd length -> True "
]
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" ## Algorithm \n " ,
" \n " ,
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" Refer to the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/linked_lists/palindrome/palindrome_solution.ipynb). If you are stuck and need a hint, the solution notebook ' s algorithm discussion might be a good place to start. "
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" ## Code "
]
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" collapsed " : true
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" %r un ../linked_list/linked_list.py \n " ,
" %lo ad ../linked_list/linked_list.py "
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]
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" class MyLinkedList(LinkedList): \n " ,
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" \n " ,
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" def is_palindrome(self): \n " ,
" # TODO: Implement me \n " ,
" pass "
]
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" source " : [
" ## Unit Test "
]
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" \n " ,
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" \n " ,
" **The following unit test is expected to fail until you solve the challenge.** "
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]
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{
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" # %lo ad test_palindrome.py \n " ,
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" import unittest \n " ,
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" \n " ,
" \n " ,
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" class TestPalindrome(unittest.TestCase): \n " ,
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" \n " ,
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" def test_palindrome(self): \n " ,
" print( ' Test: Empty list ' ) \n " ,
" linked_list = MyLinkedList() \n " ,
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" self.assertEqual(linked_list.is_palindrome(), False) \n " ,
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" \n " ,
" print( ' Test: Single element list ' ) \n " ,
" head = Node(1) \n " ,
" linked_list = MyLinkedList(head) \n " ,
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" self.assertEqual(linked_list.is_palindrome(), False) \n " ,
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" \n " ,
" print( ' Test: Two element list, not a palindrome ' ) \n " ,
" linked_list.append(2) \n " ,
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" self.assertEqual(linked_list.is_palindrome(), False) \n " ,
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" \n " ,
" print( ' Test: General case: Palindrome with even length ' ) \n " ,
" head = Node( ' a ' ) \n " ,
" linked_list = MyLinkedList(head) \n " ,
" linked_list.append( ' b ' ) \n " ,
" linked_list.append( ' b ' ) \n " ,
" linked_list.append( ' a ' ) \n " ,
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" self.assertEqual(linked_list.is_palindrome(), True) \n " ,
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" \n " ,
" print( ' Test: General case: Palindrome with odd length ' ) \n " ,
" head = Node(1) \n " ,
" linked_list = MyLinkedList(head) \n " ,
" linked_list.append(2) \n " ,
" linked_list.append(3) \n " ,
" linked_list.append(2) \n " ,
" linked_list.append(1) \n " ,
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" self.assertEqual(linked_list.is_palindrome(), True) \n " ,
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" \n " ,
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" print( ' Success: test_palindrome ' ) \n " ,
" \n " ,
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" \n " ,
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" def main(): \n " ,
" test = TestPalindrome() \n " ,
" test.test_palindrome() \n " ,
" \n " ,
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" \n " ,
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" if __name__ == ' __main__ ' : \n " ,
" main() "
]
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" cell_type " : " markdown " ,
" metadata " : { } ,
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" ## Solution Notebook \n " ,
" \n " ,
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" Review the [Solution Notebook](http://nbviewer.ipython.org/github/donnemartin/interactive-coding-challenges/blob/master/linked_lists/palindrome/palindrome_solution.ipynb) for a discussion on algorithms and code solutions. "
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]
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