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14 lines
289 B
C
14 lines
289 B
C
// 蛮力字符串匹配
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int BruteForceStringMatch(vector<char>& Total, vector<char>& Part)
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{
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int i, j;
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for (i = 0; i < Total.size() - Part.size(); ++i) {
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j = 0;
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while (j < Part.size() && Part[j] == Total[i + j]) {
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++j;
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if (j == Part.size())
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return i;
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}
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}
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return -1;
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} |