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71 lines
1.4 KiB
C++
71 lines
1.4 KiB
C++
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// 斐波那契查找
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#include "stdafx.h"
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#include <memory>
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#include <iostream>
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using namespace std;
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const int max_size=20;//斐波那契数组的长度
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/*构造一个斐波那契数组*/
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void Fibonacci(int * F)
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{
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F[0]=0;
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F[1]=1;
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for(int i=2;i<max_size;++i)
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F[i]=F[i-1]+F[i-2];
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}
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/*定义斐波那契查找法*/
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int FibonacciSearch(int *a, int n, int key) //a为要查找的数组,n为要查找的数组长度,key为要查找的关键字
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{
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int low=0;
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int high=n-1;
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int F[max_size];
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Fibonacci(F);//构造一个斐波那契数组F
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int k=0;
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while(n>F[k]-1)//计算n位于斐波那契数列的位置
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++k;
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int * temp;//将数组a扩展到F[k]-1的长度
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temp=new int [F[k]-1];
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memcpy(temp,a,n*sizeof(int));
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for(int i=n;i<F[k]-1;++i)
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temp[i]=a[n-1];
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while(low<=high)
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{
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int mid=low+F[k-1]-1;
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if(key<temp[mid])
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{
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high=mid-1;
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k-=1;
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}
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else if(key>temp[mid])
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{
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low=mid+1;
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k-=2;
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}
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else
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{
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if(mid<n)
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return mid; //若相等则说明mid即为查找到的位置
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else
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return n-1; //若mid>=n则说明是扩展的数值,返回n-1
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}
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}
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delete [] temp;
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return -1;
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}
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int main()
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{
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int a[] = {0,16,24,35,47,59,62,73,88,99};
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int key=100;
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int index=FibonacciSearch(a,sizeof(a)/sizeof(int),key);
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cout<<key<<" is located at:"<<index;
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return 0;
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}
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