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61 lines
2.0 KiB
Python
61 lines
2.0 KiB
Python
#coding: utf-8
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''' mbinary
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#######################################################################
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# File : addNegaBin.py
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# Author: mbinary
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# Mail: zhuheqin1@gmail.com
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# Blog: https://mbinary.xyz
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# Github: https://github.com/mbinary
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# Created Time: 2019-06-02 22:32
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# Description:
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给出基数为 -2 的两个数 arr1 和 arr2，返回两数相加的结果。
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数字以 数组形式 给出：数组由若干 0 和 1 组成，按最高有效位到最低有效位的顺序排列。例如，arr = [1,1,0,1] 表示数字 (-2)^3 + (-2)^2 + (-2)^0 = -3。数组形式 的数字也同样不含前导零：以 arr 为例，这意味着要么 arr == [0]，要么 arr[0] == 1。
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返回相同表示形式的 arr1 和 arr2 相加的结果。两数的表示形式为：不含前导零、由若干 0 和 1 组成的数组。
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eg
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输入：arr1 = [1,1,1,1,1], arr2 = [1,0,1]
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输出：[1,0,0,0,0]
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解释：arr1 表示 11，arr2 表示 5，输出表示 16
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#######################################################################
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'''
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from nega import nega
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def addNegaBin(arr1: list, arr2: list) -> list:
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if len(arr1) < len(arr2):
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arr1, arr2 = arr2, arr1
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for i in range(-1, -len(arr2) - 1, -1):
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if arr1[i] == 1 and arr2[i] == 1:
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arr1[i] = 0
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mux = 0
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for j in range(i - 1, -len(arr1) - 1, -1):
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if arr1[j] == mux:
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mux = 1 - mux
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arr1[j] = mux
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else:
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arr1[j] = mux
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break
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else:
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arr1 = [1, 1] + arr1
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elif arr1[i] == 0 and arr2[i] == 1:
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arr1[i] = arr2[i]
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#print(arr1,arr2,i)
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while len(arr1) > 1 and arr1[0] == 0:
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arr1.pop(0)
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return arr1
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if __name__=='__main__':
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while 1:
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print("input q to quit or input x1 x2: ")
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s = input()
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if s=='q':
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break
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n1,n2 =[int(i) for i in s.split()]
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l1,l2 = nega(n1),nega(n2)
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print(n1,l1)
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print(n2,l2)
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print(f'{n1}+{n2}={n1+n2}: {addNegaBin(l1,l2)}')
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