algorithm-in-python/dynamicProgramming/max-len-of-repeated-subarra...

24 lines
749 B
Python

#coding: utf-8
''' mbinary
#######################################################################
# File : max-len-of-repeated-subarray.py
# Author: mbinary
# Mail: zhuheqin1@gmail.com
# Blog: https://mbinary.xyz
# Github: https://github.com/mbinary
# Created Time: 2019-05-27 08:25
# Description:
给两个整数数组 A 和 B ,返回两个数组中公共的、长度最长的子数组的长度。
#######################################################################
'''
def findLength(A, B):
n, m = len(A), len(B)
dp = [[0]*(m+1) for i in range(n+1)]
for i in range(1, n+1):
for j in range(1, m+1):
if A[i-1] == B[j-1]:
dp[i][j] = dp[i-1][j-1]+1
return max(max(row) for row in dp)