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Thibault Kruse 2016-08-23 11:58:03 +02:00
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CppCoreGuidelines.md
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@ -3142,10 +3142,10 @@ Here on one popular implementation I got the output:
I expected that because the call of `g()` reuses the stack space abandoned by the call of `f()` so `*p` refers to the space now occupied by `gx`.
Imagine what would happen if `fx` and `gx` were of different types.
Imagine what would happen if `fx` or `gx` was a type with an invariant.
Imagine what would happen if more that dangling pointer was passed around among a larger set of functions.
Imagine what a cracker could do with that dangling pointer.
* Imagine what would happen if `fx` and `gx` were of different types.
* Imagine what would happen if `fx` or `gx` was a type with an invariant.
* Imagine what would happen if more that dangling pointer was passed around among a larger set of functions.
* Imagine what a cracker could do with that dangling pointer.
Fortunately, most (all?) modern compilers catch and warn against this simple case.
@ -12069,7 +12069,7 @@ A `thread` that has not been `detach()`ed when it is destroyed terminates the pr
##### Enforcement
* Flag `join's for `raii_thread`s ???
* Flag `join`s for `raii_thread`s ???
* Flag `detach`s for `detached_thread`s
@ -15762,7 +15762,7 @@ Use `!=` instead of `<` to compare iterators; `!=` works for more objects becaus
// ...
}
Of course, range-for is better still where it does what you want.
Of course, range-`for` is better still where it does what you want.
##### Example
@ -16409,7 +16409,7 @@ This slowdown can be significant compared to `printf`-style output.
##### Example
cout << "Hello, World!" << endl; // two output operations and a flush
cout << "hello, World!\n"; // one output operation and no flush
cout << "Hello, World!\n"; // one output operation and no flush
##### Note