# 36. 二叉搜索树与双向链表 [NowCoder](https://www.nowcoder.com/practice/947f6eb80d944a84850b0538bf0ec3a5?tpId=13&tqId=11179&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github) ## 题目描述 输入一棵二叉搜索树,将该二叉搜索树转换成一个排序的双向链表。要求不能创建任何新的结点,只能调整树中结点指针的指向。

## 解题思路 ```java private TreeNode pre = null; private TreeNode head = null; public TreeNode Convert(TreeNode root) { inOrder(root); return head; } private void inOrder(TreeNode node) { if (node == null) return; inOrder(node.left); node.left = pre; if (pre != null) pre.right = node; pre = node; if (head == null) head = node; inOrder(node.right); } ```