# 38. 字符串的排列 [NowCoder](https://www.nowcoder.com/practice/fe6b651b66ae47d7acce78ffdd9a96c7?tpId=13&tqId=11180&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github) ## 题目描述 输入一个字符串,按字典序打印出该字符串中字符的所有排列。例如输入字符串 abc,则打印出由字符 a, b, c 所能排列出来的所有字符串 abc, acb, bac, bca, cab 和 cba。 ## 解题思路 ```java private ArrayList ret = new ArrayList<>(); public ArrayList Permutation(String str) { if (str.length() == 0) return ret; char[] chars = str.toCharArray(); Arrays.sort(chars); backtracking(chars, new boolean[chars.length], new StringBuilder()); return ret; } private void backtracking(char[] chars, boolean[] hasUsed, StringBuilder s) { if (s.length() == chars.length) { ret.add(s.toString()); return; } for (int i = 0; i < chars.length; i++) { if (hasUsed[i]) continue; if (i != 0 && chars[i] == chars[i - 1] && !hasUsed[i - 1]) /* 保证不重复 */ continue; hasUsed[i] = true; s.append(chars[i]); backtracking(chars, hasUsed, s); s.deleteCharAt(s.length() - 1); hasUsed[i] = false; } } ```