commit
bd8b6bfb14
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@ -1779,47 +1779,46 @@ public int MoreThanHalfNum_Solution(int[] nums) {
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找到第 K 个元素之后,就可以再遍历一次数组,所有小于等于该元素的数组元素都是最小的 K 个数。
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```java
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public ArrayList<Integer> GetLeastNumbers_Solution(int[] nums, int k) {
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if (k > nums.length || k <= 0)
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return new ArrayList<>();
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int kthSmallest = findKthSmallest(nums, k - 1);
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ArrayList<Integer> ret = new ArrayList<>();
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for (int val : nums)
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if (val <= kthSmallest && ret.size() < k)
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ret.add(val);
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return ret;
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}
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public ArrayList<Integer> GetLeastNumbers_Solution(int[] input, int k) {
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ArrayList<Integer> res = new ArrayList<>();
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if (k > input.length || k <= 0) return res;
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findKthSmallest(input, k - 1);
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for (int i = 0; i < k; i++) {
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res.add(input[i]);
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}
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return res;
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}
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public int findKthSmallest(int[] nums, int k) {
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private void findKthSmallest(int[] nums, int k) {
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int l = 0, h = nums.length - 1;
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while (l < h) {
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int j = partition(nums, l, h);
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if (j == k)
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break;
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if (j > k)
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h = j - 1;
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else
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l = j + 1;
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int j = paration(nums, l, h);
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if (j == k) break;
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else if (j > k) h = j - 1;
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else l = j + 1;
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}
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}
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return nums[k];
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}
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private int partition(int[] nums, int l, int h) {
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private int paration(int[] nums, int l, int h) {
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//nums[l+1,i] nums[j,h]
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int i = l, j = h + 1;
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while (true) {
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while (i < h && nums[++i] < nums[l]) ;
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while (j > l && nums[l] < nums[--j]) ;
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if (i >= j)
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break;
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while (j > l + 1 && nums[--j] > nums[l]) ;
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if (i >= j) break;
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swap(nums, i, j);
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}
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swap(nums, l, j);
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return j;
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}
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private void swap(int[] nums, int i, int j) {
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int t = nums[i]; nums[i] = nums[j]; nums[j] = t;
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}
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}
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private void swap(int[] nums, int i, int j) {
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int t = nums[i];
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nums[i] = nums[j];
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nums[j] = t;
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}
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```
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### 大小为 K 的最小堆
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