From 7545ae24b3d2aa30747cef53560941a1bba07fcd Mon Sep 17 00:00:00 2001
From: CyC2018 <1029579233@qq.com>
Date: Sat, 9 Jun 2018 21:43:10 +0800
Subject: [PATCH] auto commit

---
 notes/Leetcode-Database 题解.md | 10 +++++-----
 1 file changed, 5 insertions(+), 5 deletions(-)

diff --git a/notes/Leetcode-Database 题解.md b/notes/Leetcode-Database 题解.md
index 5fd4eadf..9bf9bf22 100644
--- a/notes/Leetcode-Database 题解.md	
+++ b/notes/Leetcode-Database 题解.md	
@@ -554,7 +554,7 @@ VALUES
 
 ```sql
 SELECT
-    C.NAME AS Customers
+    C.Name AS Customers
 FROM
     Customers C
     LEFT JOIN Orders O ON C.Id = O.CustomerId
@@ -566,11 +566,11 @@ WHERE
 
 ```sql
 SELECT
-    C.NAME AS Customers
+    Name AS Customers
 FROM
-    Customers C
+    Customers
 WHERE
-    C.Id NOT IN ( SELECT CustomerId FROM Orders );
+    Id NOT IN ( SELECT CustomerId FROM Orders );
 ```
 
 # 184. Department Highest Salary
@@ -637,7 +637,7 @@ VALUES
 
 创建一个临时表，包含了部门员工的最大薪资。可以对部门进行分组，然后使用 MAX() 汇总函数取得最大薪资。
 
-之后使用连接将找到一个部门中薪资等于临时表中最大薪资的员工。
+之后使用连接找到一个部门中薪资等于临时表中最大薪资的员工。
 
 ```sql
 SELECT