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CyC2018 2019-01-21 23:35:47 +08:00
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docs/notes/剑指 offer 题解.md
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@ -116,18 +116,8 @@ Output:
以 (2, 3, 1, 0, 2, 5) 为例，遍历到位置 4 时，该位置上的数为 2，但是第 2 个位置上已经有一个 2 的值了，因此可以知道 2 重复：
<div align="center"> <img src="pics/1.gif" width="350px"> </div><br>
<div align="center"> <img src="pics/11548084848123.gif" width="250px"> </div><br>
```text
position-0 : (2,3,1,0,2,5) // 2 <-> 1
(1,3,2,0,2,5) // 1 <-> 3
(3,1,2,0,2,5) // 3 <-> 0
(0,1,2,3,2,5) // already in position
position-1 : (0,1,2,3,2,5) // already in position
position-2 : (0,1,2,3,2,5) // already in position
position-3 : (0,1,2,3,2,5) // already in position
position-4 : (0,1,2,3,2,5) // nums[i] == nums[nums[i]], exit
```
```java
public boolean duplicate(int[] nums, int length, int[] duplication) {