From bada236d6ce0222918782840b3390c7423146490 Mon Sep 17 00:00:00 2001 From: =?UTF-8?q?=E9=99=88=E6=B4=AA=E5=B7=9E?= Date: Thu, 30 May 2019 11:52:31 +0800 Subject: [PATCH] =?UTF-8?q?Update=20Leetcode=20=E9=A2=98=E8=A7=A3=20-=20?= =?UTF-8?q?=E5=8A=A8=E6=80=81=E8=A7=84=E5=88=92.md?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit 勘误 --- docs/notes/Leetcode 题解 - 动态规划.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/docs/notes/Leetcode 题解 - 动态规划.md b/docs/notes/Leetcode 题解 - 动态规划.md index 63fc6d2e..4fe9fbbb 100644 --- a/docs/notes/Leetcode 题解 - 动态规划.md +++ b/docs/notes/Leetcode 题解 - 动态规划.md @@ -299,7 +299,7 @@ dp[4] = dp[3] + 1 = 3 综上,在 A[i] - A[i-1] == A[i-1] - A[i-2] 时,dp[i] = dp[i-1] + 1。 -因为递增子区间不一定以最一个元素为结尾,可以是任意一个元素结尾,因此需要返回 dp 数组累加的结果。 +因为递增子区间不一定以最后一个元素为结尾,可以是任意一个元素结尾,因此需要返回 dp 数组累加的结果。 ```java public int numberOfArithmeticSlices(int[] A) {