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notes/剑指 offer 题解.md
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@ -2021,6 +2021,12 @@ public int GetUglyNumber_Solution(int N) {
# 50. 第一个只出现一次的字符位置 # 50. 第一个只出现一次的字符位置
## 题目描述
在一个字符串 (1<=字符串长度 <=10000，全部由字母组成) 中找到第一个只出现一次的字符，并返回它的位置。
## 解题思路
```java ```java
public int FirstNotRepeatingChar(String str) { public int FirstNotRepeatingChar(String str) {
int[] cnts = new int[256]; int[] cnts = new int[256];