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CyC2018 2021-03-23 02:48:19 +08:00
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## 题目链接
[NowCoder](https://www.nowcoder.com/practice/c6c7742f5ba7442aada113136ddea0c3?tpId=13&tqId=11160&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/c6c7742f5ba7442aada113136ddea0c3?tpId=13&tqId=11160&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
## 题目描述

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## 题目链接
[NowCoder](https://www.nowcoder.com/practice/72a5a919508a4251859fb2cfb987a0e6?tpId=13&tqId=11163&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/72a5a919508a4251859fb2cfb987a0e6?tpId=13&tqId=11163&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
## 题目描述
@ -27,7 +27,7 @@
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/508c6e52-9f93-44ed-b6b9-e69050e14807.jpg" width="370px"> </div><br>
```java
public int RectCover(int n) {
public int rectCover(int n) {
if (n <= 2)
return n;
int pre2 = 1, pre1 = 2;

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## 题目链接
[NowCoder](https://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4?tpId=13&tqId=11161&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4?tpId=13&tqId=11161&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
## 题目描述

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## 题目链接
[NowCoder](https://www.nowcoder.com/practice/22243d016f6b47f2a6928b4313c85387?tpId=13&tqId=11162&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/22243d016f6b47f2a6928b4313c85387?tpId=13&tqId=11162&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
## 题目描述
@ -15,7 +15,7 @@
### 动态规划
```java
public int JumpFloorII(int target) {
public int jumpFloorII(int target) {
int[] dp = new int[target];
Arrays.fill(dp, 1);
for (int i = 1; i < target; i++)

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# 12. 矩阵中的路径
[NowCoder](https://www.nowcoder.com/practice/c61c6999eecb4b8f88a98f66b273a3cc?tpId=13&tqId=11218&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/69fe7a584f0a445da1b6652978de5c38?tpId=13&tqId=11218&tab=answerKey&from=cyc_github)
## 题目描述
@ -19,46 +19,60 @@
本题的输入是数组而不是矩阵二维数组因此需要先将数组转换成矩阵
```java
private final static int[][] next = {{0, -1}, {0, 1}, {-1, 0}, {1, 0}};
private int rows;
private int cols;
public class Solution {
private final static int[][] next = {{0, -1}, {0, 1}, {-1, 0}, {1, 0}};
private int rows;
private int cols;
public boolean hasPath(char[] array, int rows, int cols, char[] str) {
if (rows == 0 || cols == 0) return false;
this.rows = rows;
this.cols = cols;
boolean[][] marked = new boolean[rows][cols];
char[][] matrix = buildMatrix(array);
for (int i = 0; i < rows; i++)
for (int j = 0; j < cols; j++)
if (backtracking(matrix, str, marked, 0, i, j))
return true;
return false;
}
private boolean backtracking(char[][] matrix, char[] str,
boolean[][] marked, int pathLen, int r, int c) {
if (pathLen == str.length) return true;
if (r < 0 || r >= rows || c < 0 || c >= cols
|| matrix[r][c] != str[pathLen] || marked[r][c]) {
public boolean hasPath (String val, int rows, int cols, String path) {
if (rows == 0 || cols == 0) return false;
this.rows = rows;
this.cols = cols;
char[] array = val.toCharArray();
char[][] matrix = buildMatrix(array);
char[] pathList = path.toCharArray();
boolean[][] marked = new boolean[rows][cols];
for (int i = 0; i < rows; i++)
for (int j = 0; j < cols; j++)
if (backtracking(matrix, pathList, marked, 0, i, j))
return true;
return false;
}
marked[r][c] = true;
for (int[] n : next)
if (backtracking(matrix, str, marked, pathLen + 1, r + n[0], c + n[1]))
return true;
marked[r][c] = false;
return false;
}
private char[][] buildMatrix(char[] array) {
char[][] matrix = new char[rows][cols];
for (int r = 0, idx = 0; r < rows; r++)
for (int c = 0; c < cols; c++)
matrix[r][c] = array[idx++];
return matrix;
private boolean backtracking(char[][] matrix, char[] pathList,
boolean[][] marked, int pathLen, int r, int c) {
if (pathLen == pathList.length) return true;
if (r < 0 || r >= rows || c < 0 || c >= cols
|| matrix[r][c] != pathList[pathLen] || marked[r][c]) {
return false;
}
marked[r][c] = true;
for (int[] n : next)
if (backtracking(matrix, pathList, marked, pathLen + 1, r + n[0], c + n[1]))
return true;
marked[r][c] = false;
return false;
}
private char[][] buildMatrix(char[] array) {
char[][] matrix = new char[rows][cols];
for (int r = 0, idx = 0; r < rows; r++)
for (int c = 0; c < cols; c++)
matrix[r][c] = array[idx++];
return matrix;
}
public static void main(String[] args) {
Solution solution = new Solution();
String val = "ABCESFCSADEE";
int rows = 3;
int cols = 4;
String path = "ABCCED";
boolean res = solution.hasPath(val, rows, cols, path);
System.out.println(res);
}
}
```

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# 13. 机器人的运动范围
[NowCoder](https://www.nowcoder.com/practice/6e5207314b5241fb83f2329e89fdecc8?tpId=13&tqId=11219&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/6e5207314b5241fb83f2329e89fdecc8?tpId=13&tqId=11219&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
## 题目描述

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## 题目链接
[Leetcode](https://leetcode.com/problems/integer-break/description/)
[牛客网](https://www.nowcoder.com/practice/57d85990ba5b440ab888fc72b0751bf8?tpId=13&tqId=33257&tab=answerKey&from=cyc_github)
## 题目描述
@ -37,7 +37,7 @@ return 36 (10 = 3 + 3 + 4)
继续拆成更大的绳子可以发现都比拆成 2 3 的效果更差因此我们只考虑将绳子拆成 2 3并且优先拆成 3当拆到绳子长度 n 等于 4 也就是出现 3+1此时只能拆成 2+2
```java
public int integerBreak(int n) {
public int cutRope(int n) {
if (n < 2)
return 0;
if (n == 2)
@ -55,7 +55,7 @@ public int integerBreak(int n) {
### 动态规划
```java
public int integerBreak(int n) {
public int cutRope(int n) {
int[] dp = new int[n + 1];
dp[1] = 1;
for (int i = 2; i <= n; i++)

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# 18.2 删除链表中重复的结点
[NowCoder](https://www.nowcoder.com/practice/fc533c45b73a41b0b44ccba763f866ef?tpId=13&tqId=11209&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/fc533c45b73a41b0b44ccba763f866ef?tpId=13&tqId=11209&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
## 题目描述

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# 19. 正则表达式匹配
[NowCoder](https://www.nowcoder.com/practice/45327ae22b7b413ea21df13ee7d6429c?tpId=13&tqId=11205&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/28970c15befb4ff3a264189087b99ad4?tpId=13&tqId=11205&tab=answerKey&from=cyc_github)
## 题目描述
@ -13,22 +13,22 @@
应该注意到'.' 是用来当做一个任意字符 '\*' 是用来重复前面的字符这两个的作用不同不能把 '.' 的作用和 '\*' 进行类比从而把它当成重复前面字符一次
```java
public boolean match(char[] str, char[] pattern) {
public boolean match(String str, String pattern) {
int m = str.length, n = pattern.length;
int m = str.length(), n = pattern.length();
boolean[][] dp = new boolean[m + 1][n + 1];
dp[0][0] = true;
for (int i = 1; i <= n; i++)
if (pattern[i - 1] == '*')
if (pattern.charAt(i - 1) == '*')
dp[0][i] = dp[0][i - 2];
for (int i = 1; i <= m; i++)
for (int j = 1; j <= n; j++)
if (str[i - 1] == pattern[j - 1] || pattern[j - 1] == '.')
if (str.charAt(i - 1) == pattern.charAt(j - 1) || pattern.charAt(j - 1) == '.')
dp[i][j] = dp[i - 1][j - 1];
else if (pattern[j - 1] == '*')
if (pattern[j - 2] == str[i - 1] || pattern[j - 2] == '.') {
else if (pattern.charAt(j - 1) == '*')
if (pattern.charAt(j - 2) == str.charAt(i - 1) || pattern.charAt(j - 2) == '.') {
dp[i][j] |= dp[i][j - 1]; // a* counts as single a
dp[i][j] |= dp[i - 1][j]; // a* counts as multiple a
dp[i][j] |= dp[i][j - 2]; // a* counts as empty

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# 20. 表示数值的字符串
[NowCoder](https://www.nowcoder.com/practice/6f8c901d091949a5837e24bb82a731f2?tpId=13&tqId=11206&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/e69148f8528c4039ad89bb2546fd4ff8?tpId=13&tqId=11206&tab=answerKey&from=cyc_github)
## 题目描述
@ -41,8 +41,8 @@ false
```
```java
public boolean isNumeric(char[] str) {
if (str == null || str.length == 0)
public boolean isNumeric (String str) {
if (str == null || str.length() == 0)
return false;
return new String(str).matches("[+-]?\\d*(\\.\\d+)?([eE][+-]?\\d+)?");
}

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## 题目链接
[牛客网](https://www.nowcoder.com/practice/beb5aa231adc45b2a5dcc5b62c93f593?tpId=13&tqId=11166&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/ef1f53ef31ca408cada5093c8780f44b?tpId=13&tqId=11166&tab=answerKey&from=cyc_github)
## 题目描述
@ -15,7 +15,7 @@
方法一创建一个新数组时间复杂度 O(N)空间复杂度 O(N)
```java
public void reOrderArray(int[] nums) {
public int[] reOrderArray (int[] nums) {
// 奇数个数
int oddCnt = 0;
for (int x : nums)
@ -29,6 +29,7 @@ public void reOrderArray(int[] nums) {
else
nums[j++] = num;
}
return nums;
}
private boolean isEven(int x) {
@ -39,7 +40,7 @@ private boolean isEven(int x) {
方法二使用冒泡思想每次都将当前偶数上浮到当前最右边时间复杂度 O(N<sup>2</sup>)空间复杂度 O(1)时间换空间
```java
public void reOrderArray(int[] nums) {
public int[] reOrderArray(int[] nums) {
int N = nums.length;
for (int i = N - 1; i > 0; i--) {
for (int j = 0; j < i; j++) {
@ -48,6 +49,7 @@ public void reOrderArray(int[] nums) {
}
}
}
return nums;
}
private boolean isEven(int x) {

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# 22. 链表中倒数第 K 个结点
[NowCoder](https://www.nowcoder.com/practice/529d3ae5a407492994ad2a246518148a?tpId=13&tqId=11167&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/886370fe658f41b498d40fb34ae76ff9?tpId=13&tqId=11167&tab=answerKey&from=cyc_github)
## 解题思路

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# 27. 二叉树的镜像
[NowCoder](https://www.nowcoder.com/practice/564f4c26aa584921bc75623e48ca3011?tpId=13&tqId=11171&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7?tpId=13&tqId=11171&tab=answerKey&from=cyc_github)
## 题目描述
@ -9,12 +9,13 @@
## 解题思路
```java
public void Mirror(TreeNode root) {
public TreeNode Mirror(TreeNode root) {
if (root == null)
return;
return root;
swap(root);
Mirror(root.left);
Mirror(root.right);
return root;
}
private void swap(TreeNode root) {

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## 题目链接
[牛客网](https://www.nowcoder.com/practice/4060ac7e3e404ad1a894ef3e17650423?tpId=13&tqId=11155&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/0e26e5551f2b489b9f58bc83aa4b6c68?tpId=13&tqId=11155&tab=answerKey&from=cyc_github)
## 题目描述

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## 题目链接
[牛客网](https://www.nowcoder.com/practice/e02fdb54d7524710a7d664d082bb7811?tpId=13&tqId=11193&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
[牛客网](https://www.nowcoder.com/practice/389fc1c3d3be4479a154f63f495abff8?tpId=13&tqId=11193&tab=answerKey&from=cyc_github)
## 题目描述
@ -19,16 +19,27 @@
下面的解法中num1 num2 数组的第一个元素是用来保持返回值的... 实际开发中不推荐这种返回值的方式
```java
public void FindNumsAppearOnce(int[] nums, int num1[], int num2[]) {
public int[] FindNumsAppearOnce (int[] nums) {
int[] res = new int[2];
int diff = 0;
for (int num : nums)
diff ^= num;
diff &= -diff;
for (int num : nums) {
if ((num & diff) == 0)
num1[0] ^= num;
res[0] ^= num;
else
num2[0] ^= num;
res[1] ^= num;
}
if (res[0] > res[1]) {
swap(res);
}
return res;
}
private void swap(int[] nums) {
int t = nums[0];
nums[0] = nums[1];
nums[1] = t;
}
```