28 lines
828 B
Java
28 lines
828 B
Java
|
# 63. 股票的最大利润
|
|||
|
|
|
|||
|
|
[Leetcode](https://leetcode.com/problems/best-time-to-buy-and-sell-stock/description/)
|
|||
|
|
|
|||
|
|
## 题目描述
|
|||
|
|
|
|||
|
|
可以有一次买入和一次卖出，买入必须在前。求最大收益。
|
|||
|
|
|
|||
|
|
<img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/42661013-750f-420b-b3c1-437e9a11fb65.png" width="220px">
|
|||
|
|
|
|||
|
|
## 解题思路
|
|||
|
|
|
|||
|
|
使用贪心策略，假设第 i 轮进行卖出操作，买入操作价格应该在 i 之前并且价格最低。
|
|||
|
|
|
|||
|
|
```java
|
|||
|
|
public int maxProfit(int[] prices) {
|
|||
|
|
if (prices == null || prices.length == 0)
|
|||
|
|
return 0;
|
|||
|
|
int soFarMin = prices[0];
|
|||
|
|
int maxProfit = 0;
|
|||
|
|
for (int i = 1; i < prices.length; i++) {
|
|||
|
|
soFarMin = Math.min(soFarMin, prices[i]);
|
|||
|
|
maxProfit = Math.max(maxProfit, prices[i] - soFarMin);
|
|||
|
|
}
|
|||
|
|
return maxProfit;
|
|||
|
|
}
|
|||
|
|
```
|