2019-11-02 12:07:41 +08:00
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# 36. 二叉搜索树与双向链表
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[NowCoder](https://www.nowcoder.com/practice/947f6eb80d944a84850b0538bf0ec3a5?tpId=13&tqId=11179&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
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## 题目描述
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输入一棵二叉搜索树，将该二叉搜索树转换成一个排序的双向链表。要求不能创建任何新的结点，只能调整树中结点指针的指向。
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2019-12-06 10:11:23 +08:00
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/05a08f2e-9914-4a77-92ef-aebeaecf4f66.jpg" width="400"/> </div><br>
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2019-11-02 12:07:41 +08:00
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## 解题思路
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```java
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private TreeNode pre = null;
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private TreeNode head = null;
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public TreeNode Convert(TreeNode root) {
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inOrder(root);
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return head;
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}
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private void inOrder(TreeNode node) {
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if (node == null)
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return;
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inOrder(node.left);
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node.left = pre;
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if (pre != null)
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pre.right = node;
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pre = node;
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if (head == null)
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head = node;
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inOrder(node.right);
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}
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```
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